A milliliter (ml) is a derived metric measurement unit of volume.
This question makes no sense because pressure is not measured in mL.
Water's accepted density is 1.00 g/mL at standard temperature and pressure so depending on temperature the 1057 grams of water will occupy just about 1057 mL.
The volume of water is 118 mL, since the mass and volume of water are equivalent at room temperature.
That's going to depend on the substance, which the question neglects to identify. --------------------------------------------------- The volume of any gas at STP (pressure of 1 ATM & temp.: 0oC) is approximately 22.41 L/mol or 22,410 mL/mol. So you need to find out how much gas you have to begin with (# of moles) to find the volume of the gas at STP.
According to Boyle's Law, if you double the volume of a gas at constant temperature, the pressure is halved. So, the pressure would decrease to 190 mm Hg when the gas sample is expanded to 800 mL.
The volume will depend on the pressure and temperature, but for normal temp and press, the volume will be 93 ml if one assumes the density of water is 1 g/ml.
The mass of the Chlorine will depend upon the density of the Chlorine which depends upon the temperature and pressure of the Chlorine. Assuming stp (standard temperature and pressure) the density of Chlorine is 0.0032 g/ml. density = mass / volume → mass = volume × density = 100 ml × 0.0032 g/ml = 0.32 g.
The answer depends on the temperature and pressure. At the pressure of 1 atmosphere, at 4 deg C the volume is at its minimum volume of 5.00014 millilitres. At 20 deg C it is 5.00898 ml At 100 deg C the volume increases to 5.21703 ml.
This question makes no sense because pressure is not measured in mL.
Chlorine is a gas. Its density depends on pressure, temperature and volume of the container.
Water's accepted density is 1.00 g/mL at standard temperature and pressure so depending on temperature the 1057 grams of water will occupy just about 1057 mL.
Using the ideal gas law (PV = nRT), since the temperature is constant, the relationship between pressure and volume is inversely proportional. Therefore, if the pressure doubles from 75kPa to 150kPa, the volume will halve. The new volume would be 87.5 mL.
To calculate the new pressure required to compress the nitrogen to 500 mL from 800 mL at a constant temperature, we can use Boyle's Law, which states that pressure and volume are inversely proportional. We can set up the equation as (800 mL) * (2.0 ATM) = (500 mL) * (P), where P is the new pressure. Solving for P, the new pressure required would be 3.2 ATM.
The volume of water is 118 mL, since the mass and volume of water are equivalent at room temperature.
Based on the ideal gas law at STP (standard temperature and pressure), the volume occupied by 3.00 mmol of H2 gas would be 67.2 mL (Choice B). This calculation is done using the equation V = nRT/P, where R is the gas constant, T is the temperature, P is the pressure, n is the number of moles, and V is the volume.
If the pressure is halved from 500 kPa to 250 kPa (a decrease), we can expect the volume to double if the temperature remains constant. This means the new volume would be 400 mL when starting with an initial volume of 200 mL.
Temperature is not directly tied to volume, its related to pressure. Increasing the temperature will increase the pressure--only if volume is held constant. That is were volume and temperature are related, through pressure. However, if you increase the volume it does not change the temperature.