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Ba(NO3)2(aq) + Na2SO4(aq) ==> BaSO4(s) + 2NaNO3(aq).

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What is the name for BaNO3?

Barium nitrate.


Example of simple experiment in chemistry?

Precipitation of barium sulfate:BaCl2 + Na2SO4 = BaSO4(s) + 2 NaCl


Which salt can be prepared by a method involving precipitation?

An example is barium sulfate:BaCl2 + Na2SO4 = BaSO4 + 2 NaCl


Results for experiment of Ba(NO3)2 and Na2SO4?

Ba(NO3)2(aq) + Na2SO4(aq) ==> BaSO4(s) + 2NaNO3(aq). The reaction results in the formation of insoluble barium sulfate (BaSO4).


What is the formula when combining sodium hydroxide and sulfuric acid?

The reaction between sodium hydroxide (NaOH) and sulfuric acid (H2SO4) results in the formation of sodium sulfate (Na2SO4) and water (H2O). The balanced chemical equation is: 2NaOH + H2SO4 -> Na2SO4 + 2H2O.


Is Na2SO4 plus HCl a chemical or physical change?

The reaction between Na2SO4 and HCl is a chemical change because it results in the formation of new substances (NaCl and H2SO4) with different chemical compositions compared to the reactants.


What type of reaction is baci2 na2so4?

The reaction between BaCl2 and Na2SO4 is a double displacement reaction, also known as a precipitation reaction. This means that the cations and anions of the two compounds switch partners to form two new compounds, and one of the products, BaSO4, is insoluble and precipitates out of solution.


What are the results of acid precipitation?

The carbon mineral bondinh


What is the molality of a solution containing 10.0g of Na2SO4 dissolved in 1000.0g of water?

To find the molality, we first calculate the moles of Na2SO4: 10.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 0.0705 moles Na2SO4. Then, molality is calculated as moles of solute (Na2SO4) / kilograms of solvent (water): 0.0705 mol / 1.000 kg = 0.0705 mol/kg, which is the molality of the solution.


What is the concentration of Na2SO4 solution prepared by dissolving 5.35 g of Na2SO4 in sufficient water to give 330 ml of solution?

First.Get moles sodium sulfate.5.35 grams Na2SO4 (1 mole Na2SO4/142.05 grams)= 0.0377 moles Na2SO4-------------------------------------Second.Molarity = moles of solute/Liters of solution ( 330 mL = 0.33 Liters )Molarity = 0.0377 moles Na2SO4/0.33 Liters= 0.114 M Na2SO4=============


What condition results when condensation droplets are large enough to fall?

precipitation


How many grams of Na+are contained in 25 g of sodium sulfate (Na2SO4)?

To find the mass of Na+ in sodium sulfate (Na2SO4), we need to consider the molar ratios of Na+ in the compound. In Na2SO4, there are 2 Na+ ions for every 1 Na2SO4 unit. The molar mass of Na2SO4 is 142 g/mol, so in 25 g of Na2SO4, there are about 8.8 g of Na+.