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The structure of Galactose monosaccharide sugar is a normal chain of six carbon atoms. It is an isomer of Glucose and Fructose. Below is a structure of Galactose in open chain form:

H-C=O

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H-C-OH

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OH-C-H

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OH-C-H

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H-C-OH

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H-C-OH

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OH

To understand the pyranose ring form of Galactose, draw a hexagon, assume the joints as carbon atoms except one joint- that is an oxygen atom.

Let the joints be A, B, C, D, E, F. To the joints A, C, D, E, F, assume them to be carbon atoms, and the joint B to be oxygen atom. They are joined to each other by single bonds. Now attach -CH2OH group to carbon atom A vertically upwards and -H vertically downwards. Leave oxygen atom B as it is because its stabilised. To carbon atom C, attach -H vertically upwards and -OH group vertically downwards. Repeat this with carbon atom D; & reverse the positions of -H and -OH group in the carbon atoms E and F, as it is done in the open chain form. Actually, in very brief, you only have to show glycosidic-1,4 linkage in the open form of Galactose to express it in pyranose ring form.

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