-1 or 1 or 0 if used in the term x it is 6
In the reaction I2(s) - I2(g), the entropy increases. This is because a solid state (I2(s)) has a more ordered structure compared to the gaseous state (I2(g)), which is characterized by greater molecular motion and disorder. As the solid iodine transitions to gas, the number of accessible microstates increases, leading to a higher entropy. Thus, the process is associated with an increase in randomness and disorder.
This is a trick question because "I2" is the chemical symbol for MOLECULAR iodine (your question did not say melt Iodine, it said melt I2).Only gaseous iodine is composed of I2 molecules and as it is a gas it CAN NOT melt.
I2(g) is the symbol for iodine in its standard state (including its state symbol.)
Toward I2(s) production
The correct name for the chemical formula I2 is diiodine.
When you simplify 8 over 10 to its lowest term, the answer is 4 over 5.
No you dont
25/4
Inventions
I2
Ellipses (...) used to emulate indentation... swap (int *i1, int *i2) { /* only works for integers, i1 != i2 */ ... *i1 = *i1 ^ *i2; ... *i2 = *i1 ^ *i2; ... *i1 = *i1 ^ *i2; }
That all depends on what you mean by "simplify". Reduce the fraction to the lowest term to get: 1½ If you are referring to "reduce the term to decimal form". Then, we have 1.5.
The coefficient distribution F of I2 between H2O and CCl4 refers to the partitioning of I2 between the two solvents. It quantifies the relative solubility of I2 in each solvent and is determined experimentally using a partition coefficient measurement. The coefficient distribution F is calculated as the concentration of I2 in CCl4 divided by the concentration of I2 in H2O at equilibrium.
I2 is the chemical formula. That is diatomic iodine.
I2 is an Element. It is the chemical symbol for molecular iodine.
The balanced equation for the reaction between KI and Cl2 to form KCl and I2 is: 2KI + Cl2 -> 2KCl + I2 This equation is already balanced.
Brackets are basically the same as parentheses. If they are inside of parentheses, then you simplify that term before anything else. If they are outside of parentheses, then you simplify the terms in the parentheses first and then the term within the brackets.