Al(OH)3 is a base (Aluminum hyroxide)
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Parentheses are used for the formula Al(OH)3 to indicate that the hydroxide group (OH) is grouped together and that there are three of them bonded to the aluminum atom. This notation helps to clarify the composition and structure of the compound.
The reaction equation with conventional capitalization is: Al(OH)3 + 3 HCl -> AlCl3 + 3 H2O. The gram formula unit masses are 78.00 for aluminum hydroxide, 133.34 for aluminum chloride, 36.46 for hydrogen chloride, and 18.015 for water. Therefore, the relative mass ratios are (78.00) to [3(18.015)] or about 1.443 for the ratio of the two reactants. The mass ratio of the specified available amounts of the two reactants is 385/256 or about 1.503, which is greater than the theoretical amount. Therefore, the limiting reactant is HCl. The stoichiometric reactant mass ratio of aluminum chloride to hydrogen chloride is about 133.34/(3)(36.46) or about 1.219. Therefore, a fully reacted amount of 256 g of hydrogen chloride will produce about (1.219)(256) or about 312 g of aluminum chloride. (The provided data for masses has three significant digits, so that the answer should also have three significant digits.)
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Aluminum Hydroxide
Al(OH)3
Aluminium hydroxide - Al(OH)3
Al(OH)3 is a base (Aluminum hyroxide)
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AlOH3 is considered a base because it can accept a proton (H+ ion) in a chemical reaction, forming Al(OH)4-. Bases are substances that can donate electron pairs to form bonds with hydrogen ions, which distinguishes them from acids.
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The molar mass of AlOH3 is calculated by adding the atomic masses of each element in its chemical formula. Aluminum (Al) has a molar mass of 26.98 g/mol, oxygen (O) has a molar mass of 16.00 g/mol, and hydrogen (H) has a molar mass of 1.01 g/mol. Therefore, the molar mass of AlOH3 is 78.02 g/mol.
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That is aluminum hydroxide and as a polyatomic ion hydroxide needs to be in parenthesis. Thus; Al(OH)3 This shows aluminum's 3+ oxidation state and the three matching hydroxides 1- state. 42 grams Al(OH)3 ( 1 mole Al(OH)3/78.004 grams) = 0.538 moles Al(OH)3 As significant figures require; 0.54 moles Al(OH)3
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