If the spouse he or she has the gene needed to pass on cystic fibrosis, then yes it will have children with cystic fibrosis. If the spouse does not have that gene then the child will not have cystic fbrosis but will be a gene carrier of cystic fibrosis.
Let's do a Punnit Square. T T T TT TT t Tt Tt T is normal, and the little "t" is the recessive gene (which is being carried by one parent). Since one parent is recessive, you can see that there's a 50% chance that the offspring will have the recessive gene as well. However, note that without any straight "tt" result, there is a 0% chance that the offspring can express the Tay Sachs disorder.
CF is recessive, and as such, the gene for non-CF is dominant over this gene. The CF gene will only be expressed in the phenotype and as a characteristic if the person has two of the recessive alleles.
The phenotype associated with a recessive gene is only expressed when two copies of the gene are present. For example, if a person has both a recessive allele and a dominant allele for CF, the person does not have CF. The person only has CF if he/she has two copies of the recessive allele.
No, a baby cannot be born with a CF gene if neither parent has the gene. Cystic fibrosis is an autosomal recessive genetic disorder, meaning both parents must be carriers of the mutated CF gene in order to have a child with the condition.
The parents will both have a specific gene defect. If they do there is then a 1 in 4 chance of them having a child with cf. so if you are considering having children you should have a blood test to find out if you are a carrier of the gene causing cf. hope that helps.
Let's do a Punnit Square. T T T TT TT t Tt Tt T is normal, and the little "t" is the recessive gene (which is being carried by one parent). Since one parent is recessive, you can see that there's a 50% chance that the offspring will have the recessive gene as well. However, note that without any straight "tt" result, there is a 0% chance that the offspring can express the Tay Sachs disorder.
CF is recessive, and as such, the gene for non-CF is dominant over this gene. The CF gene will only be expressed in the phenotype and as a characteristic if the person has two of the recessive alleles.
By "another pregnancy", I assume that the parents have had one child with cystic fibrosis. As cystic fibrosis is recessive and neither parent suffers from it, they must both be carriers. That means the chances of the next baby having CF is 25%, or a one in four chance. Assuming both parents have one CF and one non-CF gene, the combinations work out: non-CF x non-CF (normal) non-CF x CF (carrier) CF x non-CF (carrier) CF x CF (cystic fibrosis sufferer) Therefore their chances of having a: normal child = 25% child who is a CF carrier = 50% child who suffers from CF = 25%
Cystic Fibrosis is recessive. If you have one CF gene and one non-CF gene, you will be a carrier but not have CF.
The phenotype associated with a recessive gene is only expressed when two copies of the gene are present. For example, if a person has both a recessive allele and a dominant allele for CF, the person does not have CF. The person only has CF if he/she has two copies of the recessive allele.
No, a baby cannot be born with a CF gene if neither parent has the gene. Cystic fibrosis is an autosomal recessive genetic disorder, meaning both parents must be carriers of the mutated CF gene in order to have a child with the condition.
Cystic fibrosis (CF) is a genetic disorder caused by mutations in the CFTR gene, which is inherited in an autosomal recessive manner. This means that a person must inherit two defective copies of the gene, one from each parent, to develop the disease. If both parents are carriers of the CF mutation, there is a 25% chance with each pregnancy that their child will have CF. Carrier testing and genetic counseling can help determine the likelihood of passing on the condition.
CF carriers do not show CF symptoms themselves, but can pass the problem CF gene to their children
The parents will both have a specific gene defect. If they do there is then a 1 in 4 chance of them having a child with cf. so if you are considering having children you should have a blood test to find out if you are a carrier of the gene causing cf. hope that helps.
If you are speaking of the rare type of rickets that is X-linked and when the mother has the gene, the chances are 1:1 or 50:50. See the link below for more information:
No, it is a hereditary disease meaning it's only in the family and oth parents have to hold the gene for the child to get CF, you have to be born with CF you can't get it like the flu. Say the mother was a carrier of the CF gene but the Dad is not, the child would only be a carrier, but if both parents are then it's likely the child will have CF
Cystic Fibrosis cannot be prevented. It is an inherited disease, so there is no possible way to prevent something inherited. One parent will be a carrier and so will the other parent, therefore resulting in the child having CF.