That's a large amount of current for a battery to use. You may want to purchase a 12V marine battery or 12V deep-cycle car battery. Or you can use a car battery charger with a 6amp minimum output.
The amperage rating for your motor is a minimum requirement. For your power source, use the highest amperage rating you can find. Whether you use a 10 amp battery or a 10 million amp battery, it [the motor] will only draw 6 amps.
The voltage is a different story. Use only 12 volts DC.
Light bulb in the home - alternating current (A/C) Light bulb in a car - direct current (D/C) Output of a battery charger - direct current Input of a battery charger - usually alternating current
A battery by itself will only supply DC output. You would need a method to convert DC to AC, such as an inverter, in simplified terms: an electronic circuit which has an oscillator to create the desired frequency then amplifies it to the desired magnitude output. Another way, which I don't know if used anymore, is a motor-generator set. A DC motor's shaft is connected to an AC generator's shaft, and the output is taken from the AC generator.
The efficiency of the motor is calculated by dividing the output power by the input power and multiplying by 100%. In this case, the efficiency would be (373/450)*100 = 82.9%. This means that the motor is operating at an efficiency of approximately 83%.
The voltage measured across every component in the circuit would take on the opposite polarity from what it was originally. If there are any diodes in the circuit, then current might stop flowing in some branches where it formerly existed, or start flowing in branches where there was no current before.
A 10 KVA 3-phase UPS will have an input and output current that depends on the specific voltage of the system. You can calculate the current by dividing the apparent power (in this case 10 KVA) by the square root of 3 multiplied by the voltage. For example, for a 208V system, the input and output current would be approximately 28.8 amps.
DC can stand for "direct current" which is what you get from a battery. dc-in would be a connection for DC input.
Light bulb in the home - alternating current (A/C) Light bulb in a car - direct current (D/C) Output of a battery charger - direct current Input of a battery charger - usually alternating current
The monitor is an output device......
A battery by itself will only supply DC output. You would need a method to convert DC to AC, such as an inverter, in simplified terms: an electronic circuit which has an oscillator to create the desired frequency then amplifies it to the desired magnitude output. Another way, which I don't know if used anymore, is a motor-generator set. A DC motor's shaft is connected to an AC generator's shaft, and the output is taken from the AC generator.
Yes if the battery can deliver enough current for enough time to be useful. You would connect the motors in parallel. If for example each motor required 1 amp and you had a 30 aHr (amp hour) battery the motors could run for about 10 hours.
Yes, that would be expected. Starting the motor takes a great deal of current, headlights much less.
The efficiency of the motor is calculated by dividing the output power by the input power and multiplying by 100%. In this case, the efficiency would be (373/450)*100 = 82.9%. This means that the motor is operating at an efficiency of approximately 83%.
I would check with the manufacturer the Battery may be getting weak or the motor is drawing more current. You are gfoing to have to take it in to have it cecked out Sorry
One AA battery would suggest a small motor, with a small drain. Anything metallic thicker than a hair would do.
Blower motor resistor is right, reason; The resistor is composed of three individual coils to control current flow. when one of the coils burn out. The current bypasses these resistors and only flows from battery voltage, to motor, to ground......
Well you would definitely need a DC motor drive with possibly a 4-20 mA input.
The current depends on what is connected to the battery's terminals. If nothing is connected to it, then there is no current, and the battery lasts quite a while. In general, the current is 1.5/resistance of the external circuit connected to the battery until that number gets too big, and then the voltage of the battery sags, because it can't deliver that much current.