You can mix them together (alloying) but these noble metals do NOT react, thus no bond is made
Yes, AgCl can be separated from NaCl by adding ammonia solution. AgCl is insoluble in ammonia, so it will precipitate out as a solid while NaCl remains in the solution. The two can then be filtered or separated by decantation.
To determine the mass of AgCl needed, first calculate the number of moles needed using the molarity equation: moles = molarity x volume (in L). Then, convert moles of AgCl to grams by using the molar mass of AgCl (107.87 g/mol for Ag and 35.45 g/mol for Cl). Finally, perform the calculation to find the grams of AgCl required.
Need more info. AgCl, however, is very poorly soluble.
The treatment of AgCl involves filtering and washing the precipitate with water to remove any impurities, then drying the AgCl to obtain a solid residue. The dried AgCl can then be weighed to determine its mass and calculate the amount of chloride in the original sample of KClO3. This information can be used to determine the percent decomposition of KClO3.
In AgCl, there is one silver atom (Ag) and one chlorine atom (Cl) in each formula unit. So, there are a total of 2 atoms in one molecule of AgCl.
AgCl is highly insoluble, as it is a precipitate.
The chemical compound name for AgCl is silver chloride.
AgCl has a higher lattice energy than AgBr because Cl- is a smaller ion than Br-, resulting in stronger electrostatic interactions in AgCl.
No, AgCl is not organic. It is an inorganic compound composed of silver and chlorine.
The mole ratio of BaCl2 to AgCl is 1:2. This means that for every 1 mole of BaCl2, 2 moles of AgCl are produced in the chemical reaction.
There's 4 moles.
AgCl is a white crystalline solid and is well known for its low solubility in water.
Yes, AgCl (silver chloride) has low solubility in water. It is sparingly soluble and forms a white precipitate when it is formed in solution.
(AgCl has Ksp = 1.8 x 10-10)-5.1 x 10-10
AgCl, or silver chloride, is a white solid at room temperature.
Yes, AgCl can be separated from NaCl by adding ammonia solution. AgCl is insoluble in ammonia, so it will precipitate out as a solid while NaCl remains in the solution. The two can then be filtered or separated by decantation.
To determine the mass of AgCl needed, first calculate the number of moles needed using the molarity equation: moles = molarity x volume (in L). Then, convert moles of AgCl to grams by using the molar mass of AgCl (107.87 g/mol for Ag and 35.45 g/mol for Cl). Finally, perform the calculation to find the grams of AgCl required.