Two - one silver and one chlorine.
The binary compound with the formula AgCl is called silver chloride. It is an inorganic compound composed of silver and chlorine atoms in a 1:1 ratio, and it is commonly used in analytical chemistry and photography.
To determine the mass of AgCl needed, first calculate the number of moles needed using the molarity equation: moles = molarity x volume (in L). Then, convert moles of AgCl to grams by using the molar mass of AgCl (107.87 g/mol for Ag and 35.45 g/mol for Cl). Finally, perform the calculation to find the grams of AgCl required.
Yes, AgCl can be separated from NaCl by adding ammonia solution. AgCl is insoluble in ammonia, so it will precipitate out as a solid while NaCl remains in the solution. The two can then be filtered or separated by decantation.
Need more info. AgCl, however, is very poorly soluble.
The treatment of AgCl involves filtering and washing the precipitate with water to remove any impurities, then drying the AgCl to obtain a solid residue. The dried AgCl can then be weighed to determine its mass and calculate the amount of chloride in the original sample of KClO3. This information can be used to determine the percent decomposition of KClO3.
A formula unit of AgCl contains 2 atoms: 1 of silver and 1 of chlorine.
in the AgCl molecule two atoms present one is Ag (i.e.Ag in +1oxidation state) & another is Cl atom(Cl in -1).
No, silver chloride (AgCl) is not a mixture. It is a compound composed of silver and chlorine atoms chemically bonded together in a fixed ratio.
Silver and chlorine form AgCl.
There's 4 moles.
AgCl is highly insoluble, as it is a precipitate.
The binary compound with the formula AgCl is called silver chloride. It is an inorganic compound composed of silver and chlorine atoms in a 1:1 ratio, and it is commonly used in analytical chemistry and photography.
To find the number of moles in 0.525g of AgCl, you need to divide the mass by the molar mass of AgCl. The molar mass of AgCl is 143.32 g/mol. moles = mass / molar mass moles = 0.525g / 143.32 g/mol moles ≈ 0.0037 mol
To determine the mass of AgCl needed, first calculate the number of moles needed using the molarity equation: moles = molarity x volume (in L). Then, convert moles of AgCl to grams by using the molar mass of AgCl (107.87 g/mol for Ag and 35.45 g/mol for Cl). Finally, perform the calculation to find the grams of AgCl required.
The chemical compound name for AgCl is silver chloride.
AgCl has a higher lattice energy than AgBr because Cl- is a smaller ion than Br-, resulting in stronger electrostatic interactions in AgCl.
To find the number of moles in 0.0688g AgCl, first calculate the molar mass of AgCl. It is 143.32 g/mol. Then divide the given mass (0.0688g) by the molar mass to get the number of moles. This gives you approximately 0.00048 moles of AgCl.