0,5 moles Cl-
it wouldn't be moles of Cl it would be Cl2 as chlorine doesn't exist as an atom it exsists as two joined to form a compound this is very easy stuff the answer is 15 moles of Cl2 as there 30 moles of Cl hope this helps learn your moles it's easy stuff
When an excess of AgNO3 solution is added to a one molar solution of CrCl(H2O)5Cl2, all the chloride ions (Cl⁻) from CrCl(H2O)5Cl2 will react with Ag⁺ ions to form AgCl precipitate. Since CrCl(H2O)5Cl2 contains 6 moles of Cl⁻ per mole of complex, the reaction will precipitate 6 moles of AgCl. Therefore, 6 moles of AgCl will be formed.
For this problem you need the atomic masses of the elements to find the molecular mass (added atomic masses). Then take the atomic mass of Cl and divide it by the molecular mass (multiplied by 100) to get a percent. This will be the percent of Cl in all compounds of HCl. Then you can use this percent and apply it to the 2 moles.H- 1.00Cl- 35.5HCl- 36.535.5 / 36.5 × 100 = 97.3% Cl in HClSo we know that in 2 moles of HCl, 97.3% of it is Cl.97.3% of 2.00 moles HCl = 1.95 moles of Cl in 2 moles HClNow we have to find out how many atoms this is (convert moles to atoms). Take the number of moles and multiply it by Avogadro's constant, 6.02 × 1023.1.95 moles Cl × 6.02 × 1023 = 1.17 × 1024atoms of Cl in 2 moles of HCl
To find the number of moles of Cl₂ in 985 g, use the molar mass of Cl₂, which is about 70.906 g/mol. The number of moles is calculated by dividing the mass by the molar mass: [ \text{moles of Cl₂} = \frac{985 \text{ g}}{70.906 \text{ g/mol}} \approx 13.9 \text{ moles} ] Since Cl₂ consists of two chlorine atoms, the mass of Cl atoms present can be calculated by multiplying the moles of Cl₂ by 2 and then by the molar mass of chlorine (approximately 35.453 g/mol), resulting in approximately 985 g of Cl atoms.
To find the number of moles in 0.0688g AgCl, first calculate the molar mass of AgCl. It is 143.32 g/mol. Then divide the given mass (0.0688g) by the molar mass to get the number of moles. This gives you approximately 0.00048 moles of AgCl.
0,5 moles Cl-
There's 4 moles.
it wouldn't be moles of Cl it would be Cl2 as chlorine doesn't exist as an atom it exsists as two joined to form a compound this is very easy stuff the answer is 15 moles of Cl2 as there 30 moles of Cl hope this helps learn your moles it's easy stuff
Mg2+ + 2 Cl- are in 1 : 2 ratio (of ions) so also 0.25 : 0.50 mole ratio
1 mole Cl = 35.453g Cl 28.4g Cl x 1mol Cl/35.453g Cl = 0.801 mole Cl
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
To find the number of moles, divide the given mass of AgCl by its molar mass. The molar mass of AgCl is 143.32 g/mol (107.87 g/mol for Ag + 35.45 g/mol for Cl). Therefore, 573.28 g ÷ 143.32 g/mol = 4 moles of AgCl.
slightly
in the AgCl molecule two atoms present one is Ag (i.e.Ag in +1oxidation state) & another is Cl atom(Cl in -1).
To find the number of moles of PCl3, you need to first calculate the number of moles of Cl atoms in 3.68 * 10^25 atoms. There are 3 Cl atoms in each molecule of PCl3, so you divide the number of Cl atoms by 3 to get the number of moles of PCl3.