answersLogoWhite

0

Those co-ordinates would place you in the country of France... to the north-east of the city of Orleans.

User Avatar

Wiki User

8y ago

What else can I help you with?

Related Questions

What city is 48N and 2E?

48N and 2E coordinates correspond to Paris, the capital city of France.


What city is located at 48N 16E?

Vienna, Austria is located at 48N 16E.


What city is located at 48n 4e?

There is no city at 48N 4E. Instead, there is a forest, which is located a few miles to the north of Bernon, France.


What city is located close to 48N and 82 W?

The closest city from the point is 44 miles away. A city named Timmins in Ontario, Canada.


Which city is 49N 2E?

Paris


What city is located at 41n and 2e?

Barcelona, Spain is located at 41°N and 2°E.


find city and country with 48n 1e?

Paris, France


What city is at 49N latitude and 2E longitude?

The city at 49N latitude and 2E longitude is Paris, France.


What city has latitude of 48 N and longitude of 13 E?

None.Salzburg is located at 47º 48' 1.80"N and 13º 2' 39.88E .... which is about 14 miles away from 48N 13E


What city is at 48N and 53W?

The city located at 48 degrees North latitude and 53 degrees West longitude is St. John's, which is the capital city of Newfoundland and Labrador in Canada. St. John's is known for its vibrant culture, colorful row houses, and stunning coastal landscapes. It is the easternmost city in North America and is a popular destination for its historical sites and outdoor activities.


Is square root 48 a rational or irrational number?

Yes, here's the proof. Let's start out with the basic inequality 36 < 48 < 49. Now, we'll take the square root of this inequality: 6 < √48 < 7. If you subtract all numbers by 6, you get: 0 < √48 - 6 < 1. If √48 is rational, then it can be expressed as a fraction of two integers, m/n. This next part is the only remotely tricky part of this proof, so pay attention. We're going to assume that m/n is in its most reduced form; i.e., that the value for n is the smallest it can be and still be able to represent √48. Therefore, √48n must be an integer, and n must be the smallest multiple of √48 to make this true. If you don't understand this part, read it again, because this is the heart of the proof. Now, we're going to multiply √48n by (√48 - 6). This gives 48n - 6√48n. Well, 48n is an integer, and, as we explained above, √48n is also an integer, so 6√48n is an integer too; therefore, 48n - 6√48n is an integer as well. We're going to rearrange this expression to (√48n - 6n)√48 and then set the term (√48n - 6n) equal to p, for simplicity. This gives us the expression √48p, which is equal to 48n - 6√48n, and is an integer. Remember, from above, that 0 < √48 - 6 < 1. If we multiply this inequality by n, we get 0 < √48n - 6n < n, or, from what we defined above, 0 < p < n. This means that p < n and thus √48p < √48n. We've already determined that both √48p and √48n are integers, but recall that we said n was the smallest multiple of √48 to yield an integer value. Thus, √48p < √48n is a contradiction; therefore √48 can't be rational and so must be irrational. Q.E.D.


What are the half-reactions for a galvanic cell with Zn and Mg electrodes?

Ni2+(aq) + 2e- Ni(s) and Mg(s) Mg2+(aq) + 2e-