The closest city from the point is 44 miles away. A city named Timmins in Ontario, Canada.
Those co-ordinates would place you in the country of France... to the north-east of the city of Orleans.
The county that contains the Florida Capitol is Leon County. It is located in the state capital, Tallahassee.
The coordinates 48N 97W point to an approximate location in the state of North Dakota, near the border with Canada. The specific area is likely a remote and sparsely populated region given its northern latitude and distance from major cities or landmarks.
New Delhi, the capital of India, is located on the Tropic of Cancer in South Asia.
Vienna, Austria is located at 48N 16E.
The city located at 46N 16E coordinates is Pécs, Hungary.
There is no city at 48N 4E. Instead, there is a forest, which is located a few miles to the north of Bernon, France.
The closest city from the point is 44 miles away. A city named Timmins in Ontario, Canada.
It is located on Capitol Hill
It is located on Capitol Hill
It's 16e + 1
48N and 2E coordinates correspond to Paris, the capital city of France.
Those co-ordinates would place you in the country of France... to the north-east of the city of Orleans.
Michigan's Capitol is located in its capital city of Lansing, located on the lower peninsula.
Montreal is a city and, therefore, has no capitol. It is located in the province of Quebec (capitol, Quebec City) in the country Canada (capitol, Ottawa)
Yes, here's the proof. Let's start out with the basic inequality 36 < 48 < 49. Now, we'll take the square root of this inequality: 6 < √48 < 7. If you subtract all numbers by 6, you get: 0 < √48 - 6 < 1. If √48 is rational, then it can be expressed as a fraction of two integers, m/n. This next part is the only remotely tricky part of this proof, so pay attention. We're going to assume that m/n is in its most reduced form; i.e., that the value for n is the smallest it can be and still be able to represent √48. Therefore, √48n must be an integer, and n must be the smallest multiple of √48 to make this true. If you don't understand this part, read it again, because this is the heart of the proof. Now, we're going to multiply √48n by (√48 - 6). This gives 48n - 6√48n. Well, 48n is an integer, and, as we explained above, √48n is also an integer, so 6√48n is an integer too; therefore, 48n - 6√48n is an integer as well. We're going to rearrange this expression to (√48n - 6n)√48 and then set the term (√48n - 6n) equal to p, for simplicity. This gives us the expression √48p, which is equal to 48n - 6√48n, and is an integer. Remember, from above, that 0 < √48 - 6 < 1. If we multiply this inequality by n, we get 0 < √48n - 6n < n, or, from what we defined above, 0 < p < n. This means that p < n and thus √48p < √48n. We've already determined that both √48p and √48n are integers, but recall that we said n was the smallest multiple of √48 to yield an integer value. Thus, √48p < √48n is a contradiction; therefore √48 can't be rational and so must be irrational. Q.E.D.