CdS2HNo3
Ni(s) | Ni2+(aq) Ag+(aq) | Ag(s)
If you mean a reaction of AgNO3 + Na(s) ==> NaNO3 + Ag(s), there would be ONE electron transferred.Ag^+ + 1e- ==> Ag(s) Reduction reaction Na(s) ==> Na^+ + 1e- Oxidation reaction
The reaction is:Ag+ + Cl- = AgCl(s)Silver chloride is an insoluble, white, photosensitive precipitate.
Ag(s)
The mass of 2,65 Ag moles is 285,85 g.
Cd^2+(aq) + 2Cl^-(aq) +2Na^+(aq) + S^2-(sq) ==> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)The 2Na^+(aq) and the 2 Cl^-(aq) are spectator ions as they appear on both sides of the equation. Thus, the NET reaction is ...Cd^2+(aq) + S^2-(aq) ==> CdS(s)What else was your question. This is classed as a double replacement reaction.
In the cell, the half-reaction for silver will be Ag+ (aq) + e- -> Ag (s) with a standard reduction potential of +0.80 V. The half-reaction for copper will be Cu2+ (aq) + 2e- -> Cu (s) with a standard reduction potential of +0.34 V. The silver half-reaction will occur at the cathode, while the copper half-reaction will occur at the anode in the cell.
Fe(s) + 3AgNO3 ---> Fe(NO3)3 + Ag(s) The oxidation # of Ag on the left is 1+ and on the right it is zero. It has gained electrons and has been reduced.
The net ionic equation is Cd2+(aq) + S2-(aq) -> CdS(s). This equation represents the actual chemical change happening in the reaction where cadmium ions and sulfide ions combine to form solid cadmium sulfide. The spectator ions, Na+ and Cl-, are present on both sides of the equation but do not participate in the reaction.
Carbon dioxide and water. 2HNO3(aq) + CaCO3(s) => Ca(NO3)2 (aq) + H2O + CO2
In silver sulfide (Ag2S), each silver (Ag) atom has an oxidation state of +1, and each sulfur (S) atom has an oxidation state of -2. This arrangement balances out the charges to form a neutral compound.
Ni(s) | Ni2+(aq) Ag+(aq) | Ag(s)
If you mean a reaction of AgNO3 + Na(s) ==> NaNO3 + Ag(s), there would be ONE electron transferred.Ag^+ + 1e- ==> Ag(s) Reduction reaction Na(s) ==> Na^+ + 1e- Oxidation reaction
The above reaction is a combination type reaction between silver (Ag) and sulfur (S)
1 mol Ag/ 107.87g Ag ---/---------------------------------------- x2=215.74g Ag / 1mol Ag 1 mol S/32.07g S --------/------------------------------------32.07g S /1 mol S total=247.81g Ag2S 215.47g Ag/247.81=.8706 87.06% Ag .8706 or 87.06% Ag x 125g Ag2S = 108.83g Ag can be produced from Ag2S
The reaction is:Ag+ + Cl- = AgCl(s)Silver chloride is an insoluble, white, photosensitive precipitate.
The balanced chemical equation for the reaction between nitric acid (HNO3) and hydrogen sulfide (H2S) to produce sulfur (S), nitric oxide (NO), and water (H2O) is: 8HNO3 + 8H2S → S8 + 8NO + 10H2O