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A negative delta H for a reaction suggests that the reaction is exothermic, meaning it releases heat to its surroundings. This implies that the products of the reaction have lower energy than the reactants.

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What determine whether a reaction took place?

Use the following equation: delta G = delta H - T*deltaS. A reaction is spontaneous if delta G is negative. A reaction will always be spontaneous (under any temperature) only if the change in enthalpy (delta H) is negative and the change in entropy (delta S) is positive. If this is not the case, the reaction will only be spontaneous (negative delta G) for a range of temperatures (or could be always non-spontaneous)


What does the delta h of a reaction represent?

Either the change (which the delta refers to) of the height (which the h represents).


Can a reaction that is endothermic with a decrease in entropy never occur spontaneously?

An endothermic reaction with a decrease in entropy may still occur spontaneously under certain conditions, particularly at high temperatures. Spontaneity is determined by the Gibbs free energy change (( \Delta G )), which combines enthalpy and entropy changes (( \Delta G = \Delta H - T \Delta S )). If the negative contribution from ( T \Delta S ) (where ( \Delta S ) is negative) is outweighed by a sufficiently large positive ( \Delta H ), the reaction may not be spontaneous. However, at lower temperatures, the reverse can be true, and such a reaction could be spontaneous.


If you need to reverse the following reactions in order for it to be an intermediate reaction in a Hess's law problem what would be the final value for the enthalpy of reaction you use for this interm?

To reverse a reaction in a Hess's Law problem, you must take the negative of the enthalpy change (( \Delta H )) for that reaction. If the original reaction has an enthalpy of ( \Delta H ), then the enthalpy value you would use for the reversed reaction as an intermediate would be (-\Delta H). This ensures that the direction of the reaction is correctly accounted for in the overall calculation.


How will temperature affect the spontaneity of a reaction positive delta h and delta s?

∆G = ∆H - T∆S and for it to be spontaneous, ∆G should be negative. If both ∆H and ∆S are positive, in order to get a negative ∆H, the temperature needs to be elevated in order to make the ∆S term greater than the ∆H term. So, I guess the answer would be "the higher the temperature, the more likely will be the spontaneity of the reaction."

Related Questions

What does it mean when delta H is a negative number?

it means that heat is released during the reaction and a + delta H means that heat is required/absorbed.


What determine whether a reaction took place?

Use the following equation: delta G = delta H - T*deltaS. A reaction is spontaneous if delta G is negative. A reaction will always be spontaneous (under any temperature) only if the change in enthalpy (delta H) is negative and the change in entropy (delta S) is positive. If this is not the case, the reaction will only be spontaneous (negative delta G) for a range of temperatures (or could be always non-spontaneous)


When is q equal to delta h in a chemical reaction?

Q is equal to delta H in a chemical reaction when the reaction is at constant pressure and temperature.


What does the delta h of a reaction represent?

Either the change (which the delta refers to) of the height (which the h represents).


Can a reaction that is endothermic with a decrease in entropy never occur spontaneously?

An endothermic reaction with a decrease in entropy may still occur spontaneously under certain conditions, particularly at high temperatures. Spontaneity is determined by the Gibbs free energy change (( \Delta G )), which combines enthalpy and entropy changes (( \Delta G = \Delta H - T \Delta S )). If the negative contribution from ( T \Delta S ) (where ( \Delta S ) is negative) is outweighed by a sufficiently large positive ( \Delta H ), the reaction may not be spontaneous. However, at lower temperatures, the reverse can be true, and such a reaction could be spontaneous.


If you need to reverse the following reactions in order for it to be an intermediate reaction in a Hess's law problem what would be the final value for the enthalpy of reaction you use for this interm?

To reverse a reaction in a Hess's Law problem, you must take the negative of the enthalpy change (( \Delta H )) for that reaction. If the original reaction has an enthalpy of ( \Delta H ), then the enthalpy value you would use for the reversed reaction as an intermediate would be (-\Delta H). This ensures that the direction of the reaction is correctly accounted for in the overall calculation.


How will temperature affect the spontaneity of a reaction positive delta h and delta s?

∆G = ∆H - T∆S and for it to be spontaneous, ∆G should be negative. If both ∆H and ∆S are positive, in order to get a negative ∆H, the temperature needs to be elevated in order to make the ∆S term greater than the ∆H term. So, I guess the answer would be "the higher the temperature, the more likely will be the spontaneity of the reaction."


What is delta h in the equation delta g delta h - t delta?

The change in enthalpy between products and reactants in a reaction


When does q equal delta h in a chemical reaction?

Q equals delta H in a chemical reaction when the reaction is at constant pressure and the temperature remains constant.


How is delta hf related to the delta h of the reaction?

The standard enthalpy change of a reaction (delta H) is related to the standard enthalpy of formation (delta Hf) of the products and reactants involved in the reaction by the equation: delta H = Σ(Products delta Hf) - Σ(Reactants delta Hf). This equation relates the enthalpy change of a reaction to the enthalpies of formation of the substances involved in the reaction.


Can one of this symbol h between endotheic and exothemic?

The symbol ( h ) typically represents enthalpy in thermodynamics. In the context of endothermic and exothermic reactions, it can be associated with changes in enthalpy. An endothermic reaction absorbs heat, resulting in a positive change in enthalpy (( \Delta h > 0 )), while an exothermic reaction releases heat, leading to a negative change in enthalpy (( \Delta h < 0 )). Therefore, while ( h ) itself is not inherently endothermic or exothermic, its change (( \Delta h )) indicates the nature of the reaction.


How can one determine the delta H of a reaction?

To determine the delta H of a reaction, one can use calorimetry to measure the heat released or absorbed during the reaction. This involves measuring the temperature change of the reaction mixture and using it to calculate the heat exchanged. The delta H value represents the change in enthalpy of the reaction.