a noble gas electrom cpnfiguration look like an other !!! loook.
a lithium conguratiom 2,1
neon group 8: 2,8
the same !!!
Sodium has 11 electrons, and one valence electron To achieve noble gas configurations, it would have to gain 7 electrons, for a total of 18 like Argon has. But this gain is impossible. So Sodium loses one electron to look like Neon which has 10.
it all depends on the electron configuration if it is positive or negative, you have to look at the transition metals and valence electrons and determine the charge and use the formula n-11s^2 2s^2 2p^6 3s^2 3p^6 3d^10
If you know the name of the gas then look at a periodic table the noble gases are the one in the far right column or group 18 on the table The noble gases are very unreactive to other elements.
No, that electron configuration does not exist. After the 3p orbital fills with electrons, the next lowest energy orbital is 4s. After 4s contains 2 electrons, then 3d can accept electrons, upto 10. The element with this electron configuration is zinc, one of the transitional metals. Although 3d is full, those electrons can be 'valence' electrons and given to non-metals to form ions, such as Zn+2 or Zn+4. So 3d really acts like a 4th shell orbital and will still be quite reactive even when full. To see just how reactive these electrons are, look at the youtube videos embedded in this site: http://www.chemicool.com/elements/zinc.html.
Eu - EuropiumAtomic Weight: 151.965Oxidation States: 3, 2Electron Configuration: [Xe]4f7,6s2Noble gas notations are used because the electron configuration of these noble gases in too long ... this short cut is used ...
The electron configuration of polonium is [Xe]4f14.5d10.6s2.6p4.
Sodium has 11 electrons, and one valence electron To achieve noble gas configurations, it would have to gain 7 electrons, for a total of 18 like Argon has. But this gain is impossible. So Sodium loses one electron to look like Neon which has 10.
it all depends on the electron configuration if it is positive or negative, you have to look at the transition metals and valence electrons and determine the charge and use the formula n-11s^2 2s^2 2p^6 3s^2 3p^6 3d^10
A sulfide ion (S2-) must gain two electrons to achieve a noble gas electron configuration, similar to that of a stable, inert gas such as argon. This transfer allows the sulfide ion to fill its valence shell with eight electrons, satisfying the octet rule.
If you know the name of the gas then look at a periodic table the noble gases are the one in the far right column or group 18 on the table The noble gases are very unreactive to other elements.
No, that electron configuration does not exist. After the 3p orbital fills with electrons, the next lowest energy orbital is 4s. After 4s contains 2 electrons, then 3d can accept electrons, upto 10. The element with this electron configuration is zinc, one of the transitional metals. Although 3d is full, those electrons can be 'valence' electrons and given to non-metals to form ions, such as Zn+2 or Zn+4. So 3d really acts like a 4th shell orbital and will still be quite reactive even when full. To see just how reactive these electrons are, look at the youtube videos embedded in this site: http://www.chemicool.com/elements/zinc.html.
If you mean 1s22s22p3, you would refer to the periodic table. Using 2p3, you would look at the second period (row), look at the p block, and count 3 elements to the right to find nitrogen.
Eu - EuropiumAtomic Weight: 151.965Oxidation States: 3, 2Electron Configuration: [Xe]4f7,6s2Noble gas notations are used because the electron configuration of these noble gases in too long ... this short cut is used ...
B WRONG in my opinion New Answer D which has 11 electrons and thus is most likely to lose 1 to get to a noble gas electron configuration. Losing 1 electron it would gain a charge of + 1. Look on the periodic table. Na (sodium) has 11 electrons. You can see it only needs to lose 1 and only 1 to gain noble gas configuration and thus have full outer electron shell. THus it would be easiest for it to lose an electron. Thus Na is the answer. Thus the one with 11 electrons is the answer. THus D is the Answer
Noble gas envy is a fun term used to explain how all the elements on the periodic table want to "look like" the Noble gases. Why? Because noble gases have an outer electron configuration of s2p6 - their outer s and P subshells are full with 8 electrons. This is a stable state. The other elements will either lose, gain or share electrons with other elements to attain 8 outer electrons. Example element 9 is fluorine with 9 total electrons, but it's outer shell only has 7. It will gain an extra electron to "look like" Neon, which has 8 outer electrons. Fluorine is still fluorine, but now it has a -1 charge and is a fluorine ion. Metal elements will lose electrons until they have only 8 outer shell electron and become positively charged.
electron configuration with complete outer shells first three layers' limits are 2, 8, and 8
To determine the number of valence electrons in an atom using its electron configuration, look at the highest energy level (n) in the electron configuration. The number of electrons in this energy level is the number of valence electrons.