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It depends on what you make p equal to. P is usually the frequency of the dominant allele, which makes q the frequency of the recessive allele, but they can be switched. As long as p is one frequency and q is the other, the formula will work.
So if you have the dominant allele frequency (A) =.6 then the recessive allele frequency (a) =.4, because p+q=1
When you plug the frequencies into the hardy-weinberg equation
p^2 +2(p)(q) + (q)^2 = 1
then you have (0.6)^2 + 2(0.4)(0.6) + (0.4)^2 = 1
(0.6)^2 = 0.36 which is the frequency of dominant homozygotes
2(0.4)(0.6)=0.48 which is the frequency of heterozygotes
(0.)^2 = 0.16 which is the frequency of recessive homozygotes
If you have a population of 100 people, these frequencies would mean that:
36 people would be AA
48 people would be Aa
16 people would be aa
Which would mean that 36+48=84 people would exhibit the dominant trait and 16 people would show the recessive trait.
What else can I help you with?
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It is not an equation, but q2 meaning q^2 represents q being multiplied by itself.
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Without an equality sign the given information can't be defined as an equation.
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The units of q in the given equation are not specified.
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What does the answer to an equation represent?
The solution is the answer to an equation.
