second
Mercury's acceleration of gravity in m/s^2 is 3.59
Generally, Acceleration is Force divided by Mass. Therefore, acc. = 1000/65 = 15.38 m/sec squared = 15.36 m/s2.
Her final speed is 14.5 m/s. The kinematics equation v = at + v0 will be useful here. Note that t is the time measured in seconds, a is the acceleration, v0 is the initial velocity, and v is the velocity after t seconds (the final velocity). We are given that v0 = 10 m/s, a = 0.500 m/s2, and t = 9 s. Using the above kinematics equation we get v = (0.500 m/s2)(9 s) + 10 m/s = 14.5 m/s. Since speed = |velocity|, then her final speed = |14.5 m/s| = 14.5 m/s.
the velocity term of m/s is meters per second hopefully this is what you were asking
Yes. You could have two objects with the same final velocity (momentum, if they have mass), but having each one accelerated differently. Imagine object A starts from 5 m/s, and is accelerated over 1 second with acceleration of 20 m/s2 to attain a final velocity of 25 m/s. Now, imagine object B starts from 15 m/s, and gets an acceleration over 1 second of 10 m/s2 to attain the final velocity of 25 m/s. Both end up with the same velocity, but had different accelerations.
120kmh divided by 3,6 makes it 33.333 M/s and 33.333M/s divided by 18 seconds is 1.85M/s^2
The acceleration due to gravity on the earth, known as g, is 9.8m/s2 or 9.8m/s/s, which means that a falling object falls with an increasing velocity of 9.8m/s every second, or 9.8m/s/s, which means 9.8 meters/second/second. m/s/s can be written as m/s2, because m/s/s means m/s ÷ s/1 = m/s x 1/s = m/s2.
Acceleration = (change in speed) divided by (time interval).A = 5/4 = 1.25 m/s2
Change in velocity: (28 m/s) - (5 m/s) = 23 m/s Change in velocity divided by acceleration: (23 m/s) / (4.5 m/s2) = 5.111 seconds.
24 (m/s) / 18 s = 1.33 m/s/s or 1.33 m/s224 (m/s) / 18 s = 1.33 m/s/s or 1.33 m/s224 (m/s) / 18 s = 1.33 m/s/s or 1.33 m/s224 (m/s) / 18 s = 1.33 m/s/s or 1.33 m/s2
Metres per second squared (m/s^2 , m/s2 )
(9.8 m/s2)(8 s) = 78.4 m/s
The equation for centripetal acceleration is a = v2/r, where a is acceleration, v is velocity in m/s, and r is the radius of the circle in meters. So the dimension of the acceleration a = (m/s)2/m = m2/s2/m, which gives m/s/s or m/s2. The direction of the acceleration is toward the center of the circle.
1 [N] = 1 [kg] * 1 [m/s2]. Answer: an acceleration of 1 [m/s2].
1 way is meters per second squared. [m/s2(the 2 is an exponent)] That is the only way i know. another way is meters per second, per second again [ m/s/s ] ; weird huh? hope that helps
B -1.92 m/s2
v = a X t. a = 9.8 m/s2 (acceleration) and t = time. At t = 2 seconds, v = (9.8 m/s2) X (2 s) = 19.8 m/s. At t = 4 seconds, v = (9.8 m/s2) X (4 s) = 39.6 m/s. [ANSWER: at t = 2 s, v = 19.8 m/s ; at t = 4 s, v = 39.6 m/s. ]