An electron can have quantum numbers that specify its energy level (n), angular momentum (l), magnetic moment (m_l), and spin (m_s). The principal quantum number (n) can take positive integer values (1, 2, 3, ...), which correspond to different energy levels in an atom. For example, an electron in the third energy level would have (n = 3). The other quantum numbers would depend on the specific subshell and orientation of the electron within that energy level.
the quantum number n determines the energy of an electron in a hyrdogen atom.
A 2p electron
An electron cannot have the quantum numbers ( n=1, \ell=1, m_\ell=0, m_s=-\frac{1}{2} ) because the principal quantum number ( n ) must be a positive integer and the azimuthal quantum number ( \ell ) must satisfy ( 0 \leq \ell < n ). Since ( n=1 ) allows only ( \ell=0 ), the specified ( \ell=1 ) is not permissible. Therefore, the set of quantum numbers violates the rules of quantum mechanics, making it impossible for an electron to possess them.
The quantum numbers provided (n=3, l=0, m=10, ms=-1/2) are not valid for an electron. The principal quantum number (n) can be any positive integer, but the azimuthal quantum number (l) must be in the range (0 \leq l < n), meaning (l) can only be 0, 1, or 2 for (n=3). Additionally, the magnetic quantum number (m) must satisfy (-l \leq m \leq l), so for (l=0), (m) can only be 0. Thus, the combination of quantum numbers is not possible.
Electrons cannot have the same set of quantum numbers as another electron in the same atom due to the Pauli exclusion principle. This means that no two electrons can have identical values for the principal quantum number (n), azimuthal quantum number (l), magnetic quantum number (m_l), and spin quantum number (m_s) simultaneously. For example, if one electron has the quantum numbers n=2, l=1, m_l=0, and m_s=+1/2, no other electron in the same atom can have those exact same values.
L-1 electron configuration
A 3s electron
A 4d electron; that is for apex :)
the quantum number n determines the energy of an electron in a hyrdogen atom.
Principal quantum numbers (n).
A 2p electron
The quantum numbers for the seventeenth electron of Argon would be n=3 (principal quantum number), l=1 (azimuthal quantum number), ml=0 (magnetic quantum number), and ms= -1/2 (spin quantum number).
The last electron in a copper atom has the quantum numbers n=3, l=2, ml=0, and ms=+1/2. The quantum numbers represent the energy level (n), sublevel (l), orbital orientation (ml), and electron spin (ms) of the electron, respectively.
An electron cannot have the quantum numbers ( n=1, \ell=1, m_\ell=0, m_s=-\frac{1}{2} ) because the principal quantum number ( n ) must be a positive integer and the azimuthal quantum number ( \ell ) must satisfy ( 0 \leq \ell < n ). Since ( n=1 ) allows only ( \ell=0 ), the specified ( \ell=1 ) is not permissible. Therefore, the set of quantum numbers violates the rules of quantum mechanics, making it impossible for an electron to possess them.
The correct quantum numbers for the 7th electron of chlorine (Cl) are n=3 (principal quantum number), l=0 (azimuthal quantum number), m_l=0 (magnetic quantum number), and m_s=+1/2 (spin quantum number).
The last electron in gold is located in the 6s orbital. Therefore, the quantum numbers for this electron would be n=6 (principal quantum number), l=0 (azimuthal quantum number), ml=0 (magnetic quantum number), and ms=+1/2 (spin quantum number).
A 3s electron