Group 1- as the configuration is ns1. The Kr in the question indicates the Krypton core. The 5s1 is the clue - the period number is the same as the principal quantum number (in this case 5) so the element is in group 1 and period 5 - so it is rubidium.
The noble gas notation for antimony is [Kr] 4d10 5s2 5p3, where [Kr] represents the electron configuration of krypton (a noble gas) that comes before the electron configuration of antimony.
The notation "5s² 4d¹⁰ 5p³" represents the electron configuration of an element in the periodic table. It indicates that the element has two electrons in the 5s subshell, ten electrons in the 4d subshell, and three electrons in the 5p subshell. This configuration corresponds to the element Antimony (Sb), which is found in group 15 of the periodic table and has an atomic number of 51.
Antimony has 5 energy levels. The electron configuration for antimony is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 4f14 5s2 5p3.
there are 51 electrons in all. So the atomic number of the element is 51 and the element is antimony.
Sc i believe is the one u trying to answer.. woop a 2nd chem question.. lucky i take chem haha :P
The electronic configuration of stibium (antimony) is: [Kr]4d10 5s2 5p3.
The noble gas notation for antimony is [Kr] 4d10 5s2 5p3, where [Kr] represents the electron configuration of krypton (a noble gas) that comes before the electron configuration of antimony.
The notation "5s² 4d¹⁰ 5p³" represents the electron configuration of an element in the periodic table. It indicates that the element has two electrons in the 5s subshell, ten electrons in the 4d subshell, and three electrons in the 5p subshell. This configuration corresponds to the element Antimony (Sb), which is found in group 15 of the periodic table and has an atomic number of 51.
Antimony has 5 energy levels. The electron configuration for antimony is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 4f14 5s2 5p3.
there are 51 electrons in all. So the atomic number of the element is 51 and the element is antimony.
Sc i believe is the one u trying to answer.. woop a 2nd chem question.. lucky i take chem haha :P
The noble gas configuration for antimony (Sb) is [Kr] 4d^10 5s^2 5p^3.
Antimony Sb atom number 51, electronconfiguration:per shell: (K,L,M,N,O) = 2, 8, 18, 8+10, 5per orbital: [1s2, 2s2 2p6, 3s2 3p6 3d10, 4s2 4p6]4d10, 5s2 5p3short writing: [Kr] 4d10 5s2 5p3
The noble gas configuration of antimony is [Kr] 4d^10 5s^2 5p^3. This means that antimony has 3 valence electrons in its outermost energy level.
Sb (antimony) has 51 electrons. Its noble gas notation is [Kr] 4d10 5s2 5p3
An antimony (Sb) atom has five valence electrons in its outermost shell, which is the 5th shell with an electron configuration of [Kr] 4d10 5s2 5p3. In the 5p subshell, there are three electrons, and they occupy separate orbitals due to Hund's rule, resulting in three unpaired electrons. Therefore, an Sb atom has three unpaired electrons.
[Kr] 4d10 5s2 5p3