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How does the entropy change in the reaction 2C2H2(g) plus 5O2(g) 4CO2(g) plus 2H2O(l)?
In the reaction 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(l), the entropy decreases. This is because the reactants consist of gaseous molecules, which have higher entropy due to their greater freedom of movement, while the products include liquid water, which has lower entropy. Additionally, there is a reduction in the number of gas molecules from 7 (2 C2H2 + 5 O2) to 4 (4 CO2), further contributing to the decrease in disorder. Overall, the transition from gas to liquid and the reduction in the number of gas molecules results in a net decrease in entropy.
What happens to the entropy in the reaction l2(s)--l2(g)?
In the reaction ( \text{I}_2(s) \rightarrow \text{I}_2(g) ), entropy increases. This is because the transition from solid iodine to gaseous iodine involves a change from a more ordered state (solid) to a more disordered state (gas), where the molecules have greater freedom of movement and occupy a larger volume. As a result, the overall entropy of the system increases during this phase change.
What would happen to the entropy in the reaction 2O3 3O 2?
In the reaction 2O₃ → 3O₂, the entropy increases. This is because two molecules of ozone (O₃) decompose into three molecules of oxygen (O₂), resulting in an increase in the number of gas molecules. Since entropy is a measure of disorder or the number of ways to arrange particles, the formation of more gas molecules leads to greater disorder, thus increasing the overall entropy of the system.
Will this entropy change by positive or negative n½ g 3h½ g æ 2nh¾ g?
To determine the change in entropy for the reaction represented by the expression ( n^{1/2} g , + , 3h^{1/2} g , \leftrightarrow , 2nh^{3/4} g ), we need to consider the number of moles of gas on each side of the equation. If the total number of gaseous moles increases in the products compared to the reactants, the entropy change will be positive, indicating an increase in disorder. Conversely, if the number of moles decreases, the entropy change will be negative. Without specific coefficients or more context, we cannot definitively conclude the sign of the entropy change.
What happens to the entropy in the reaction I2(s) - and gt I2(g)?
In the reaction I₂(s) → I₂(g), the entropy increases. This is because the transition from a solid to a gas involves a significant increase in disorder and the number of available microstates. In the solid phase, iodine molecules are closely packed and have limited motion, while in the gas phase, they move freely and occupy a larger volume, resulting in higher entropy.
What describes the entropy change of gas reaction?
if there is an increase in the number of gas molecules , then ^S > 0
Which of the following describes the entropy change of a gas reaction?
If there is an increase in the number of gas molecules, then S > 0.
How does entropy change in gas reactions?
Reactions that increase the moles of gas will increase in entropy.
How do you predict delta s?
delta s (change in entropy) is positive when.... -you go from a solid to a liquid -you go from a liquid to a gas -when you go from a solid to a gas -when there are more mols of products than mols of reactant the change in entropy is negative when the reverse of the above happens
What happens to the entropy in the reaction l2(s)l2(g)?
The entropy increases in this reaction, as the solid reactant (I2(s)) is becoming a gas (I2(g)), which represents a higher degree of disorder and randomness on a molecular level. The increased entropy contributes to the spontaneity of the reaction.
What happens to the entropy in the reaction I2 s I2 g?
The entropy of the system increases during the sublimation of I2(s) to I2(g) because the randomness and disorder of the gas phase is higher compared to the solid phase. Therefore, the entropy of the reaction is positive.
What would happen to the entropy in the reaction 2O3 g 3O2 g?
It increases
What happens to the entropy in the reaction l2(s) l2(g)?
The entropy increases, as going from a solid to a gas increases disorder or randomness in the system. This is because gases have more freedom of movement and energy compared to solids.
What reaction would have an increase in entropy?
At high temperature the entropy increase.
What would happen to entropy in a solid to gas reaction?
It increases; more freely moving particles.
How does the entropy change in the reaction 2C2H2(g) plus 5O2(g) 4CO2(g) plus 2H2O(l)?
In the reaction 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(l), the entropy decreases. This is because the reactants consist of gaseous molecules, which have higher entropy due to their greater freedom of movement, while the products include liquid water, which has lower entropy. Additionally, there is a reduction in the number of gas molecules from 7 (2 C2H2 + 5 O2) to 4 (4 CO2), further contributing to the decrease in disorder. Overall, the transition from gas to liquid and the reduction in the number of gas molecules results in a net decrease in entropy.
How does change in phase affect entropy changes in a reaction?
A change in phase (e.g. solid to liquid) typically involves an increase in entropy due to an increase in molecular disorder and freedom of movement. However, entropy changes can vary depending on the specific conditions of the reaction.
