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What happens to the entropy in the reaction l2(s)l2(g)?
The entropy increases in this reaction, as the solid reactant (I2(s)) is becoming a gas (I2(g)), which represents a higher degree of disorder and randomness on a molecular level. The increased entropy contributes to the spontaneity of the reaction.
Ask us anythingUse the reaction I2(s) I2(g) H 62.4 kJmol S 0.145 kJ(molK) for question 10. What can be said about the reaction at 500 K?
At 500 K, the reaction will favour the formation of gaseous I2 since the positive change in enthalpy indicates the reaction is endothermic. The positive change in entropy suggests an increase in disorder, further favoring the formation of gaseous I2 at higher temperatures.
Which direction of the reaction equilibrium is favored at 298 K room temperature use the reaction I2 solid to I2 gas when H 62.4 kJmol and S 0.145 kJmolK?
I2(s) --> I2(g); dH=62.4kJ/mol; dS=0.145kJ/mol. The reaction will favor the product at this temperature. Your entropy is positive and your enthalpy is also positive, so this reaction will not be spontaneous at all temperatures. But at room temperature, which is 298K, it will be spontaneous and proceed left to right. (this is the sublimation of iodine)
What happens to the entropy in the reaction l2(s) l2(g)?
The entropy increases, as going from a solid to a gas increases disorder or randomness in the system. This is because gases have more freedom of movement and energy compared to solids.
How does the entropy change in the reaction 2C3H6 g 9O2 g 6CO2 g 6 H2O g?
The entropy INCREASES. There are more moles in the products than in the reactants.
What happens to the entropy in the reaction l2(s)l2(g)?
The entropy increases in this reaction, as the solid reactant (I2(s)) is becoming a gas (I2(g)), which represents a higher degree of disorder and randomness on a molecular level. The increased entropy contributes to the spontaneity of the reaction.
How does the entropy change in the reaction 2C3H6 (g) plus 9O (g) 6CO2(g)?
The entropy increase in this reaction.
Ask us anythingUse the reaction I2(s) I2(g) H 62.4 kJmol S 0.145 kJ(molK) for question 10. What can be said about the reaction at 500 K?
At 500 K, the reaction will favour the formation of gaseous I2 since the positive change in enthalpy indicates the reaction is endothermic. The positive change in entropy suggests an increase in disorder, further favoring the formation of gaseous I2 at higher temperatures.
Which direction of the reaction equilibrium is favored at 298 K room temperature use the reaction I2 solid to I2 gas when H 62.4 kJmol and S 0.145 kJmolK?
I2(s) --> I2(g); dH=62.4kJ/mol; dS=0.145kJ/mol. The reaction will favor the product at this temperature. Your entropy is positive and your enthalpy is also positive, so this reaction will not be spontaneous at all temperatures. But at room temperature, which is 298K, it will be spontaneous and proceed left to right. (this is the sublimation of iodine)
What happens to the entropy in the reaction l2(s) l2(g)?
The entropy increases, as going from a solid to a gas increases disorder or randomness in the system. This is because gases have more freedom of movement and energy compared to solids.
Hydrogen gas reacts with iodine vapor equation?
The reaction between hydrogen gas and iodine vapor forms hydrogen iodide gas. The balanced chemical equation for this reaction is: H2(g) + I2(g) -> 2HI(g)
How does the entropy change in the reaction 2C3H6 g 9O2 g 6CO2 g 6 H2O g?
The entropy INCREASES. There are more moles in the products than in the reactants.
Will this entropy change by positive or negative N2 (g) 3h2 (g) 2nh3 (g)?
The reaction N2 (g) + 3H2 (g) → 2NH3 (g) shows an increase in entropy because it involves an increase in the number of gaseous molecules from 2 to 4. Therefore, the entropy change for this reaction is positive.
What would happen to the entropy in the reaction 2O3 g 3O2 g?
It increases
which of the following reaction would have an increase in entropy?
CH4(g) + H2O(g) CO(g) + 3H2(g)
What reaction would cause decrease in entropy?
CO(g)+3H2(g)->CH4(g)+H2O(g)
What would cause entropy decreasing a reaction?
CO(g)+3H2(g)->CH4(g)+H2O(g)
