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When you talk about the energy of any electromagnetic radiation in terms of its

frequency, you're talking about the energy of a single photon.

8.2 x 1019 J is a bit more than 1,000 times the energy that the Braidwood nuclear

generating station south of Chicago produces in a year.

In order for a single photon to have 8.2 x 1019 J of energy, its frequency would have to be

8.2 x 1019/Planck's Konstant = 8.2 x 1019/6.62608 x 10-34 = 1.2375 x 1053 Hz.

That's about 1034 times the frequency a photon needs in order to be called a

gamma-ray. At that frequency, the wavelength is about 2.422 x 10-45 meter,

and that's something like 10-27 the size of an electron.

Perhaps you meant to type 8.2 x 10minus 19 J.

The frequency of photon with that energy is

8.2 x 10-19/6.62608 x 10-34 = 1.238 x 1015 Hz.

and its wavelength is about 242 nanometers.

That would be a photon in the mid-range ultraviolet.

If you want a beam of light that carries your alleged 8.2 x 10plus 19 J,

you just need more of these photons ... like 1038 of them.

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How are frequency and energy of waves related?

Frequency and energy are related by the following: E = hf where h is Planck's constant, E is the energy in J, and f is the frequency in Hz. Remember that the product of any wavelength and its frequency is equal to the speed of light.


An electron loses 2.5 x 10-15 J of energy and emits a photon What is the frequency of the photon that is emitted?

Photon energy = (Planck's konstant) x (frequency) nu = E / h E = 2.5 x 10-15 J h = 6.626 x 10-34 J-s nu = (2.5 x 10-15 J) / (6.626 x 10-34 J-s) = (2.5 x 10-15 / 6.626 x 10-34) (J / J - s) = 3.773 x 1019 Hz = 3.773 x 1010 GHz


If the photon has a frequency of 4 x 1015 Hz how did the energy of the electron change?

If the change in energy of electron is totally exhibited as a photon then the energy = h times frequency. h = 6.626 x 10 to -34 J s Simply multiply h and frequency you would get the energy in joule


What is the frequency in hertz and the energy in joules of an x-ray photon with a wavelength of 2.32 Å?

For the frequency, first convert the wavelength to meters (divide the number of Angstroms by 1010), then use the formula: wavelength x frequency = speed. Using the speed of light in this case. Solving for frequency: frequency = speed / wavelength. To get the photon's energy, multiply the frequency times Planck's constant, which is 6.63 x 10-34 (joules times seconds).


How do you calculate the energy of the photons released to make a line in an atomic emission spectrum?

The energy of the photons released during an atomic emission spectrum can be calculated using the equation (E = h \nu), where (E) is the energy of the photon, (h) is Planck's constant ((6.626 \times 10^{-34} , \text{J s})), and (\nu) is the frequency of the emitted light. The frequency can be related to the wavelength ((\lambda)) of the light using the equation (\nu = \frac{c}{\lambda}), where (c) is the speed of light ((3.00 \times 10^8 , \text{m/s})). By measuring the wavelength of the emitted light, you can determine its frequency and subsequently calculate the energy of the photons.

Related Questions

What is the frequency of light that has an energy of 2.7 x 10-16 J?

The frequency of light with energy 2.7 x 10^-16 J is f = E/h, where h is Planck's constant (6.626 x 10^-34 J*s). Substituting the values gives a frequency of approximately 4.07 x 10^17 Hz.


What is the energy of a photon the emits a light of frequency 6.42 1014 Hz?

4.25 10-19 j


What is the energy of a photon that emits a light of frequency 4.471014?

The energy of a photon is given by E=hf, where h is Planck's constant (6.626 x 10^-34 J*s) and f is the frequency of light. Thus, the energy of the photon emitting light of frequency 4.471014 Hz is approximately 2.97 x 10^-33 Joules.


What is the energy of a photon that emits a light of frequency 4.47X 1014 Hz?

2.96 x 10^-19 J


What is the energy of a photon that emits a light of frequency 4.47 x 1014 Hz?

2.96 x 10-19 J


What is the energy of a photon that emits a light of frequency energy 7.211014 Hz?

The energy of a photon is given by E = hf, where h is Planck's constant (6.626 x 10^-34 J.s) and f is the frequency of the light. Substituting the given frequency of 7.211014 Hz into the equation, we find that the energy of the photon is approximately 4.79 x 10^-33 J.


How much energy does a 445 nm wave of light have (The speed of light in a vacuum is 3.00 108 ms and Planck's constant is 6.626 10-34 J and bulls.)?

The energy of a photon can be calculated using the formula E = hf, where h is Planck's constant and f is the frequency of the wave. Since frequency = speed of light / wavelength, the energy of a 445 nm wave of light would be approximately 2.79 x 10^-19 J.


What is the energy of a quantum of light with a frequency of 7.39 x 1014 Hz?

The energy of a quantum of light is given by the equation E = hf, where E is the energy, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency. Substituting the values, the energy of a quantum of light with a frequency of 7.39 x 10^14 Hz would be approximately 4.90 x 10^-19 Joules.


What is the energy of photon that emits a light of frequency (4.47)(10 exponent 14) Hz?

The energy is 2,9619.e-19 J.


What is the energy of a photon of 325nm?

The energy of a photon is determined by the equation E = hf, where E is energy, h is Planck's constant (6.626 x 10^-34 J s), and f is the frequency of the photon. First, calculate the frequency of the photon using the speed of light equation, c = λf. Then, substitute the frequency into the energy equation to find the energy of the photon.


What is the energy of a photon that emits a light frequency of 7.21 x 1014 Hz?

The energy of a photon can be calculated using the formula E = hf, where E is the energy, h is Planck's constant (6.626 x 10^-34 J.s), and f is the frequency of the light. Plugging in the values, the energy of a photon emitting a light frequency of 7.21 x 10^14 Hz is approximately 4.85 x 10^-19 J.


How are frequency and energy of waves related?

Frequency and energy are related by the following: E = hf where h is Planck's constant, E is the energy in J, and f is the frequency in Hz. Remember that the product of any wavelength and its frequency is equal to the speed of light.