In this case, the strongest reducing agent is Cl-, followed by Br-, and then I-. This is because the larger the atomic radius, the easier it is to lose an electron, making them better reducing agents.
Cl2 is larger than F2 because chlorine (Cl) has a larger atomic radius than fluorine (F), resulting in larger molecules overall.
Magnesium isn't smaller than chlorine, it's larger. The atomic radius for magnesium is 145 pm and the atomic radius for chlorine is 79 pm. Both magnesium and chlorine are in the third period of the periodic table. The trend for atomic radius is that the elements generally get smaller as you move from left to right across the table in the same period.
From the given elements, Mg has the largest atomic radius, hence the size.
K :- potassiumCl:- ChlorineO:- OxygenBr:- Bromine
S has a larger radius. The atomic radius decreases across a period.
Chlorine has a larger atomic radius than fluorine. This is because chlorine has its outermost electrons in the 3rd energy level, which is farther from the nucleus, and fluorine has its outermost electrons in the 2nd energy level, which is closer to the nucleus.
Bromine (Br) is more reactive than chlorine (Cl) and selenium (Se). Bromine has a lower ionization energy and a larger atomic radius compared to chlorine and selenium, making it more willing to participate in chemical reactions.
Calcium has the larger atomic radius than chlorine. Calcium has four energy levels, whereas chlorine has three energy levels. The higher the energy level, the farther it is from the atomic nucleus.
No. It is difficult to get an accurate measure of the size of a single atom. One estimate based on the molecular Cl2 and Br2 bond lengths has the relative sizes as Cl 100 pm; Br 115 pm. Another way is to calculate the radius theoretically one source estimates Cl, 79pm and Br 94pm.
The halogen bromine (Br) is more soluble in water at all temperatures compared to chlorine (Cl). This is due to bromine's higher molecular weight and larger atomic radius, which makes it more polarizable and allows for stronger interactions with water molecules.
In this case, the strongest reducing agent is Cl-, followed by Br-, and then I-. This is because the larger the atomic radius, the easier it is to lose an electron, making them better reducing agents.
Atomic radius increases going down the periodic table and going from right to left, meaning that Fr (Francium) has the largest atomic radius and He (Helium) has the smallest. Therefore, Cl<S<P<Si<Al So the answer is Cl
Cl2 is larger than F2 because chlorine (Cl) has a larger atomic radius than fluorine (F), resulting in larger molecules overall.
The atomic weight of Br (Bromine) is the sum of the atomic weights of Cl (Chlorine) and I (Iodine). This is because bromine falls between chlorine and iodine in the periodic table, thus its atomic weight is approximately the average of the atomic weights of chlorine and iodine.
It is a difference between the empirical and the calculated atomic radius of an element; also all the values are only approximates. The empirical atomic radius of sulphur, phosphorous and chlorine is 100 pm. The calculated atomic radius of phosphorous is 98 pm.
The chloride ion (Cl-) is larger than the oxygen ion (O2-). This is because the chloride ion has more electrons than the oxygen ion, resulting in a larger atomic radius and hence a larger ionic radius.