Ferrous oxide is FeO. 80/72 = x/56 x = 62.2 g
7,44 x 104 kg of lead(IV) oxide is equal to 31,1.10e4 moles.
There is no elemental calcium in calcium oxide. Calcium oxide is a compound made up of calcium and oxygen atoms bonded together. When calcium oxide reacts with water, it forms calcium hydroxide, which contains calcium ions but not elemental calcium.
3.18 mol 70.0gN2O x 1mol N2O/44.013g x 2mol N/1mol N2O
FeO for ferrous oxide, ( iron(II) oxide); Fe2O3 for ferric oxide, (iron(III) oxide) and Fe3O4 for ferrous ferric oxide, (iron (II,III) oxide)
Ferrous oxide is FeO. 80/72 = x/56 x = 62.2 g
The number of particles of X in the formula for an oxide of X depends on the specific compound. For example, in carbon dioxide (CO2) there are two particles of carbon (C), and in water (H2O) there is one particle of oxygen (O). The general formula for an oxide of X is XnO where n represents the number of particles of X.
7,44 x 104 kg of lead(IV) oxide is equal to 31,1.10e4 moles.
10% w/w = 10g/ 100g = x /3400g x = amount of drug in 3400 g or i would just say 10% of 3400 = 340 g of zinc oxide is needed to be 10% strength now how much do you have to add of zinc oxide to get 15% strength?? so you will end up with 340g of original PLUS x amount of new zinc oxide = the total drug you will use. so (340 + x) and to find percentage of drug over entire medication ... you would say (340 + x) over (3400 + x) and (3400 + x) = total medication with the additional zinc oxide you will want to add. finally: total drug/ total medication(Rx) = the new percentage strength sooo --> you wanted 15% to be the zinc oxide (drug) (340 + x) / (3400 + x) = 15% drug or better yet: (340 + x) / (3400 + x) = 15g/ 100g since 15% is 15 out of 100 so CROSS MULTIPLY and solve for x: (340 + x) * 100 = (3400 + x) * 15 34000 + 100 x = 51000 + 15 x--> 85 x = 17000 x = 200 so 200 grams of zinc oxide must be added to the original to get your 15% of drug strength.
The chemical formula for sodium oxide is Na2O (with the '2' written in subscript). So in one formula unit of sodium oxide, there is one sodium and two oxygen. 1 mole of sodium oxide would have 3 x 6.02 x 10^23 = 1.81 x 10^24 atoms.Sodium oxide is made of sodium and oxygen atoms. The chemical formula of it is Na2O. There are 3 atoms in 1 molecule of Na2O.
'CaO' ; 1 x atom of calcium (Ca) 1 x atom of oxygen (O).
0.34 moles Na2O (1 mole O 2-/1 mole Na2O)(6.022 X 1023/1 mole O 2-) 2.1 X 1023 ions of oxygen ================
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That depends on which molecule you are referring to when you say "iron oxide". All of the following are correctly referred to as "iron oxide" - either as iron (II) oxide or iron (III) oxideFeOFe3O4Fe4O5Fe5O6Fe5O7Fe25O32Fe13O19Fe2O3Assuming you are looking to find the number of grams of oxygen and iron respectively required to produce 100 grams of "iron oxide" you would have to refer to the atomic weights of iron (55.845) and oxygen (~ 15.999 or 16) and then use them to find the molecular weight of the chosen form of iron oxide. From that you would calculate the number of grams required from the formula:For FemOng oxygen =100 g x 1 mole FemOn/([55.845 x m] + [15.999 x n])g FemOn x n moles O/mole FemOn x 15.999 g O/mole O.g iron =100 g x 1 mole FemOn/([55.845 x m] + [15.999 x n])g FemOn x m moles Fe/mole FemOn x 55.845 g Fe/mole Fe.
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Anne Skancke has written: 'X-ray studies of some wolfram oxide phosphate glasses' -- subject(s): Glass, Tungsten oxide phosphate, X-ray crystallography