That depends on which molecule you are referring to when you say "iron oxide". All of the following are correctly referred to as "iron oxide" - either as iron (II) oxide or iron (III) oxide
FeO
Fe3O4
Fe4O5
Fe5O6
Fe5O7
Fe25O32
Fe13O19
Fe2O3
Assuming you are looking to find the number of grams of oxygen and iron respectively required to produce 100 grams of "iron oxide" you would have to refer to the atomic weights of iron (55.845) and oxygen (~ 15.999 or 16) and then use them to find the molecular weight of the chosen form of iron oxide. From that you would calculate the number of grams required from the formula:
For FemOn
g oxygen =
100 g x 1 mole FemOn/([55.845 x m] + [15.999 x n])g FemOn x n moles O/mole FemOn x 15.999 g O/mole O.
g iron =
100 g x 1 mole FemOn/([55.845 x m] + [15.999 x n])g FemOn x m moles Fe/mole FemOn x 55.845 g Fe/mole Fe.
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
To determine the amount of calcium needed, you need to balance the chemical equation for the reaction between calcium and water. The equation is Ca + 2H2O → Ca(OH)2 + H2. Then, convert the mass of water to moles, use the stoichiometry of the balanced equation to find the moles of calcium required, and convert that to grams of calcium.
First, calculate the number of moles of K2CO3 in 10.0 grams. Next, write and balance the chemical equation for the reaction between HCl and K2CO3. Use the stoichiometry of the balanced equation to determine the number of moles of HCl required to react with the moles of K2CO3. Finally, use the molarity of the HCl solution to calculate the volume needed.
To produce 4 grams of table salt (NaCl), you would need 2 moles of Na and 1 mole of Cl2. This corresponds to 46 grams of Na and 71 grams of Cl2. This would total 117 grams of reactants (2Na + Cl2) to produce 4 grams of NaCl.
To find the amount of Cr2O3 required to produce 83.4 grams of Cr2S3, you should start by determining the molar ratio between Cr2O3 and Cr2S3. This ratio is 2:1. Next, calculate the molar mass of Cr2S3, which is 480.32 g/mol. Using the molar ratio and molar masses, you can find that you need 160.11 grams of Cr2O3 to produce 83.4 grams of Cr2S3.
The balanced chemical equation for the reaction between iron and oxygen to produce Fe2O3 is 4Fe + 3O2 -> 2Fe2O3. From the equation, we see that 3 moles of oxygen react with 4 moles of iron to produce 2 moles of Fe2O3. Therefore, to find the grams of oxygen needed, we need to calculate the molar mass of Fe2O3 and then determine the number of grams needed using the mole ratio from the balanced equation.
To determine the amount of calcium needed, you need to balance the chemical equation for the reaction between calcium and water. The equation is Ca + 2H2O → Ca(OH)2 + H2. Then, convert the mass of water to moles, use the stoichiometry of the balanced equation to find the moles of calcium required, and convert that to grams of calcium.
800 g oxygen are needed.
To find the grams of nitrogen dioxide needed, first calculate the moles of nitrogen monoxide using Avogadro's number. Then, use the balanced chemical equation to determine the moles of nitrogen dioxide required. Finally, convert moles to grams using the molar mass of nitrogen dioxide.
To determine the grams of hydrazine (N2H4) needed to produce 96.0 grams of water (H2O), we start with the balanced chemical equation for the reaction: 2 N2H4 + 2 O2 → 4 H2O + N2. From this equation, we see that 2 moles of hydrazine produce 4 moles of water. The molar mass of water is approximately 18 g/mol, so 96.0 g of water corresponds to 5.33 moles of water. This means 2.67 moles of hydrazine are required, which equals about 66.3 grams of hydrazine (with a molar mass of 32.05 g/mol).
First, calculate the number of moles of K2CO3 in 10.0 grams. Next, write and balance the chemical equation for the reaction between HCl and K2CO3. Use the stoichiometry of the balanced equation to determine the number of moles of HCl required to react with the moles of K2CO3. Finally, use the molarity of the HCl solution to calculate the volume needed.
To produce 4 grams of table salt (NaCl), you would need 2 moles of Na and 1 mole of Cl2. This corresponds to 46 grams of Na and 71 grams of Cl2. This would total 117 grams of reactants (2Na + Cl2) to produce 4 grams of NaCl.
To find the amount of Cr2O3 required to produce 83.4 grams of Cr2S3, you should start by determining the molar ratio between Cr2O3 and Cr2S3. This ratio is 2:1. Next, calculate the molar mass of Cr2S3, which is 480.32 g/mol. Using the molar ratio and molar masses, you can find that you need 160.11 grams of Cr2O3 to produce 83.4 grams of Cr2S3.
The balanced chemical equation for the reaction is: 4Fe + 3O2 -> 2Fe2O3 From the equation, it can be seen that 3 moles of O2 are required to react with 4 moles of Fe. Therefore, to determine the grams of O2 required to react with 100 g Fe, you would need to use stoichiometry to find the answer.
Start with a balanced equation: C5H12 + 8O2 --> 5CO2 + 6H2OFind the number of moles of water in 72 g: FW of H2O is 18 g/mol so 72g/18g/mol is 4 molRecall from the balanced equation the number of moles of water produced for each mole of Pentane: 6 waters for each pentaneYou produce 4 moles of water so the ratio from the balanced equation says you will need 4/6 mole of pentaneFind the FW of the pentane: It (coincidentally) comes 72 grams/molSo, 0.67 mol of pentane times 72 g/mol will give the final answer of 48.24 grams
Given the balanced equation2Al + 6HBr --> 2AlBr3 + 3H2In order to find how many grams of HBr are required to produce 150g AlBr3, we must convert from mass to mass (mass --> mass conversion).150g AlBr3 * 1 mol AlBr3 * 6 molecules HBr = 136.52 or 137g HBr----------- 266.6g AlBr3 * 2 molecules AlBr3
To find out how many grams of N2 are needed to produce 1.7 grams of NH3, you need to look at the balanced chemical equation for the reaction. For the reaction N2 + 3H2 -> 2NH3, the molar ratio of N2 to NH3 is 1:2. So you would need half the number of grams of N2 as NH3, which is 0.85 grams of N2.