The mass of iron depends on how much is present.
FeS is not a chemical equation but a chemical formula; FeS is the chemical formula of iron sulfide.
Assuming this is the reaction: FeS + H2 --> H2S + Fe, the molar mass of H2S is 34g/mol, so you have about 4.4mol of it. Because the equation features reagents in a 1:1 ratio, this means you will require 4.4mol of FeS. FeS has a molar mass of 88g/mol, and 88x4.4=387.2g FeS required.
FeS is Iron II Sulfide Fe2S3 is Iron III Sulfide
Iron sulfides are: FeS, FeS2, Fe3S4.
The balanced chemical equation for the reaction between iron and sulfur to form iron(II) sulfide is: Fe + S -> FeS This equation shows that one iron atom reacts with one sulfur atom to form one molecule of iron(II) sulfide.
FeS is not a chemical equation but a chemical formula; FeS is the chemical formula of iron sulfide.
The two possible formulaunits for Iron Sulfide are; FeS, and Fe1S1
The balanced chemical equation for the reaction between iron and sulfur to form iron sulfide is: 8 Fe + S8 -> 8 FeS Given that 5.6g of iron completely reacts with excess sulfur, we can calculate the mass of iron sulfide produced. Using stoichiometry, we find that 5.6g of Fe corresponds to 5.6g of FeS being produced, as the molar ratio between Fe and FeS is 1:1.
iron
There are two atoms in the compound FeS: Sulfur and iron.
FeS
Iron II sulfide
iron.
There are two elements in FeS: iron (Fe) and sulfur (S).
The reaction between iron and sulfur to form iron(II) sulfide is: Fe + S -> FeS
Assuming this is the reaction: FeS + H2 --> H2S + Fe, the molar mass of H2S is 34g/mol, so you have about 4.4mol of it. Because the equation features reagents in a 1:1 ratio, this means you will require 4.4mol of FeS. FeS has a molar mass of 88g/mol, and 88x4.4=387.2g FeS required.
Yes, Fe (iron) plus S (sulfur) equals FeS (iron sulfide). If the iron ion is iron(ll) then it is iron(ll) sulfide; if it is iron(lll), then it iron(lll) sulfide.