Nickel (III) Bromide
To find the number of moles of NiBr3 in a given mass (g), you can use the formula: [ \text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} ] First, calculate the molar mass of NiBr3 by adding the molar mass of nickel (approximately 58.69 g/mol) and three times the molar mass of bromine (approximately 79.90 g/mol). The total molar mass of NiBr3 is approximately 298.39 g/mol. Then divide the mass of NiBr3 by this molar mass to find the number of moles.
NiBr3
The formula for copper II nitrate trihydrate is Cu(NO3)2•3H2O. This compound contains one copper atom (Cu), two nitrate ions (NO3), and three water molecules (H2O) in its structure.
Rust is Fe2O3 ....it can not be removed by 1.HCl 2.H2So4 3.Edta..... but can remove by Oxalic Acid H2C2O4 Fe2O3(s) + 6 H2C2O4(aq) → 2 Fe(C2O4)3 3−(aq) + 3 H2O(l) + 6 H+(aq)
A coefficient in a chemical formula tells you how many molecules there are. For example, 3Co2. The number 3 which comes before the C tells you that there are 3 molecules. The coefficient is the first number. This molecules consist of 3 C atoms (1 multiplied by the coefficient 3), and 6 O atoms( 2 multiplied by the coefficient 3) Another example: H= one hydrogen atom H2= one molecule made of 2 hydrogen atoms bonded together 3H20= three molecules consisting of two hydrogen atoms bonded to one oxygen atom
NiBr3 stands for nickel(III) bromide. It is a chemical compound composed of nickel and bromine, where nickel has an oxidation state of +3.
NiBr3
Cu(NO3)2 ・3H20
About 3h20.
c6H12O6 + 3hco3- + 3h+ >>> 6co2 + 3h20 + 3ch4
Iron oxide is produced.The chemical reaction is given as 2Fe+3H20=Fe2O3+3H2
Your formulas are not correct.
NI(NO3)3+pbbr4nibr3+pb(no3)4
the distance from Paris to the Mont-Saint-Michel is 358 km by the A13 motorway. The driving time is 3H20.
3:20 --> 3h20 (or 18h20, if it's in the afternoon) --> trois heures vingt
The reaction of ethanol with NaOH and iodine will yield iodoethane (ethyl iodide) as the product. The alcohol group in ethanol will be replaced by the iodine atom in the presence of NaOH.
The correct answer is: C5H12 + 8O2 5CO2 + 6H2O.