Since jerk is defined as the derivative (the rate of change) of acceleration, in the case of the area under the curve, it is the other way round: the integral (area under the curve) for jerk is the acceleration.
Acceleration can be determined from a velocity-time graph by calculating the slope of the line on the graph. The steeper the slope, the greater the acceleration. If the graph is curved, acceleration can be calculated by finding the tangent to the curve at a specific point.
It depends on the force acting on the body in question. Depending on which way you want your independent and dependent variables set up, the equation is either Acceleration = Force/mass or Mass = Force/acceleration
The acceleration of the ball can be estimated by calculating the slope of the velocity versus time graph. If the graph is a straight line, the slope represents the acceleration. The steeper the slope, the greater the acceleration. If the graph is curved, the instantaneous acceleration can be estimated by finding the slope of the tangent line at a specific point on the curve.
Concave up. "Acceleration is increasing with time" tells us that the derivative of acceleration is positive. Since acceleration is the derivative of velocity, this means that the second derivative of velocity is positive. By definition, having a non-negative second derivative means that velocity is concave up.
Actually, a car always accelerates on a curve. This is because acceleration, like the velocity it alters, is a vector that has both magnitude and direction. Since taking a curve involves a change of direction, there must be an acceleration to alter the direction; otherwise, the car can only continue straight.
Yes, the degree of a curve can affect acceleration. In a curve with a higher degree, the change in direction is sharper, which can lead to higher acceleration as the vehicle needs to adjust its speed to navigate the curve effectively. In contrast, curves with lower degrees may require less acceleration due to their more gradual changes in direction.
Calculate the gradient of the curve which will give the acceleration. Change the sign of the answer to convert acceleration into retardation.
To calculate the speed of an object moving around a curve, you can use the centripetal acceleration formula: (a = v^2 / r), where (a) is the centripetal acceleration, (v) is the speed of the object, and (r) is the radius of the curve. To find the speed ((v)), you need to know the radius of the curve and the centripetal acceleration acting on the object.
On a distance-time graph, acceleration is represented by a curve that shows the slope increasing over time. If the graph is a straight line, it indicates constant speed, while a curved line indicates changing speed. The steeper the curve, the greater the acceleration; if the curve flattens, it suggests a decrease in acceleration. In contrast, if the graph shows a downward curve, it may indicate deceleration.
The graph of velocity-time is the acceleration.
If the vehicle is gaining speed on that gentle curve, yes. Otherwise, no.
that is acceleration at a particular point in time. If acceleration is changing with time, it is the slope of the velocity vs. time curve.
Acceleration
The slope of the tangent to the curve on a velocity-time graph represents the acceleration of an object. Positive slope indicates acceleration in the positive direction, negative slope indicates acceleration in the negative direction, and zero slope indicates constant velocity.
the slope of a tangent to the curve of a V vs T graph is acceleration at that point in time. the derivative of the function for the V vs T graph would be the function for acceleration at any given time
The rate of Change in acceleration.