the slope of a tangent to the curve of a V vs T graph is acceleration at that point in time. the derivative of the function for the V vs T graph would be the function for acceleration at any given time
The slope of the tangent to the curve on a velocity-time graph represents the acceleration of an object. Positive slope indicates acceleration in the positive direction, negative slope indicates acceleration in the negative direction, and zero slope indicates constant velocity.
The instantaneous speed at a specific point on a speed-time graph is the slope of the tangent to the curve at that point. It represents the speed of an object at that exact moment in time. This can be determined by calculating the gradient at that particular point.
You cannot because a displacement-time graph is concerned only with radial motion: displacement from a fixed point of reference. Any transverse motion is completely ignored. Thus, if you had a body going around in a circle about the point of reference, its speed would be recorded zero!
To calculate velocity from a position-time graph, you can find the slope of the line tangent to the curve at a specific point. This slope represents the instantaneous velocity at that point. Alternatively, you can calculate the average velocity over a specific time interval by finding the change in position divided by the change in time.
The area under the curve in a graph or chart represents the total value or quantity of the data being measured within that specific range or interval.
You find the slope of the tangent to the curve at the point of interest.
The slope of the tangent to the curve on a velocity-time graph represents the acceleration of an object. Positive slope indicates acceleration in the positive direction, negative slope indicates acceleration in the negative direction, and zero slope indicates constant velocity.
Tangent line is a graph. This graph is to gather data.
It will measure acceleration in the direction towards or away from the origin.
No, average velocity is the total displacement divided by the total time taken. The slope of the tangent to the curve on a velocity-time graph at a specific instant of time gives the instantaneous velocity at that moment, not the average velocity.
The answer will depend on the context. If the curve in question is a differentiable function then the gradient of the tangent is given by the derivative of the function. The gradient of the tangent at a given point can be evaluated by substituting the coordinate of the point and the equation of the tangent, though that point, is then given by the point-slope equation.
Slope = (vertical change)/(horizontal change), commonly referred to as rise/run. If the graph is a straight line, then you can count squares or measure how much change in vertical, over a specified change in horizontal. If it is a curve, then you need to have a tangent line (a line that touches the curve at a specific point and has the same slope as the line), then you can determine the slope of that line using the method described, above.
When you graph a tangent function, the asymptotes represent x values 90 and 270.
You can't, since the slope of the graph means average velocity and the area of the graph has no meaning. The only way to find instantaneous velocity from position-time gragh is by plugging the data into the kinematic equations to get the answer. Edit: Actually you can if you take the derivative of the equation of the curve it will give you the equation of the velocity curve
The variable plotted along the vertical axis is the distance in the first case, speed in the second. The gradient of (the tangent to) the distance-time graph is the speed while the area under the curve of the speed-time graph is the distance.
Draw a tangent to the curve at the point where you need the gradient and find the gradient of the line by using gradient = up divided by across
From v = u - (a*t)then:a = (v-u) / tSelect a point on a time(x) - velocity(y) graph, calculate the slope of a tangent to the line at this point , this is the rate of acceleration at that point.On a data driven curve approximation is used.On a mathematical curve differential calculus can be used.