An anilinium is the cation formed by protonating the amino group of aniline.
The dissociation reaction of anilinium ion (C6H5NH3+) in water is: C6H5NH3+ (aq) -> C6H5NH2 (aq) + H+ (aq). In this reaction, anilinium ion breaks apart into aniline (C6H5NH2) and a hydrogen ion (H+).
Aniline (C6H5NH2) is a better nucleophile compared to anilinium (C6H5NH3+) because aniline is a stronger base due to the lone pair on the nitrogen that can participate in nucleophilic attacks. Anilinium is less nucleophilic because the positively charged nitrogen reduces its nucleophilic character.
Aniline reacts with acetic acid to form anilinium acetate salt. The amino group in aniline reacts with the acetic acid to form anilinium ion, and the acetate ion is the conjugate base of acetic acid. This reaction is an acid-base reaction resulting in the formation of a salt.
Anilinium chloride is more soluble in water than aniline. This is because anilinium chloride is a salt that dissociates into ions in water, making it more likely to interact with water molecules through ion-dipole interactions. On the other hand, aniline is a neutral molecule that can only interact with water through weaker dipole-dipole interactions.
The salt formed when aniline is treated with sulfuric acid is anilinium sulfate, which can be represented by the formula (C6H5NH3)2SO4. In this salt, the aniline molecule has been protonated by the acid to form the anilinium cation (C6H5NH3+).
Since tha pka of the aniline ion is equal to 4.6, the anilinium ion is a stronger acid than the methylaminium ion, and aniline (c6h5nh2) is a weaker base than methylamine (ch3nh2).
due to we do this reaction in acidic condition here the formation of anilinium ion takesplace which is deactivating group then if we add nitration mixture substitution takes place at meta position means we don't get 4-nitroaniline
Aniline on heating with Ferric chloride forms Ferric anilide and HCl. 3C6H5-NH2 + FeCl3 = (C6H5-NH)3Fe + 3HCl
Aniline is soluble in hydrochloric acid because it reacts with the acid to form anilinium chloride, a salt that is water-soluble. This reaction involves protonation of the nitrogen atom in aniline by the HCl, making the resulting salt soluble in water due to its increased polarity compared to the parent compound.
In acid, the nitrogen gets protonated making the chloride (if using hydrochloric acid) salt of aniline, which is soluble. In a basic solution, the nitrogen is not protonated, so the solubility is much lower.
Yes, all phenols and naphthols (i.e., phenolic -OH group) are soluble in alkalis.
Alkyl groups are slightly electron donating. The methyl groups on the amine in N,N dimethylaniline contribute electron density to the nitrogen lone pair, making it more likely to reach out and grab a proton (ie more basic).