Kb = [CH3NH3 +] [OH-] / [CH3NH2]
If you added less than the amount needed in part (b) of K2SO3, what would be the limiting reactant? If you added more than the amount needed in part (b) of K2SO3, what would be the limiting reactant? Which situation would create the most SO2 gas?excess HClexcess K2SO3 excess H2Oexcess KClperfectly matched amounts of HCl and K2SO3
the answer is 49.2
I would tell, no reaction will occur the way the question has been asked.
the balanced equation is Na2S2O3 plus H2O2 yields 2NaOH plus H2S2O3 plus O2.
Kb = [CH3NH3 +] [OH-] / [CH3NH2]
6.6 x 10-9
2NaOHaq + 2HClaq --> 2NaClaq + H2Ol is the perfect balanced equatiion,except the solubility (aq) of NaCl, so it is notNaCls but NaClaq
If you added less than the amount needed in part (b) of K2SO3, what would be the limiting reactant? If you added more than the amount needed in part (b) of K2SO3, what would be the limiting reactant? Which situation would create the most SO2 gas?excess HClexcess K2SO3 excess H2Oexcess KClperfectly matched amounts of HCl and K2SO3
76 plus 54 plus 92 plus 88 plus 76 plus 88 plus 75 plus 93 plus 92 plus 68 plus 88 plus 76 plus 76 plus 88 plus 80 plus 70 plus 88plus 72 equal 1,440
The answer is 672.
27x3+6=87.
132
It is 77
102
That is 27 x 9 = 243
189