The equilibrium constant (Kb) for the reaction of methylamine (CH3NH2) with water to form the methylammonium ion (CH3NH3+) and hydroxide ion (OH-) is a measure of the base strength of methylamine in aqueous solution. It quantifies the extent to which methylamine accepts a proton from water. The reaction can be represented as: CH3NH2(aq) + H2O(l) ⇌ CH3NH3+(aq) + OH-(aq). Kb is calculated using the concentrations of the products divided by the concentration of the reactants at equilibrium.
Kb = [CH3NH3 +] [OH-] / [CH3NH2]
The base dissociation constant (Kb) for methylamine (CH3NH2) in water is a measure of its ability to accept a proton (H+) from water, forming CH3NH3+ and hydroxide ions (OH-). The equilibrium expression for this reaction is given by Kb = [CH3NH3+][OH-] / [CH3NH2]. For methylamine, Kb is approximately 4.2 × 10^-4 at 25°C, indicating its relatively weak basicity compared to stronger bases.
The base dissociation constant (Kb) for methylamine (CH3NH2) can be determined from its equilibrium reaction with water, where CH3NH2 accepts a proton to form CH3NH3+ and hydroxide ions (OH-). The Kb value indicates the strength of CH3NH2 as a base, reflecting its ability to generate OH- in solution. For methylamine, Kb is approximately 4.2 × 10^-4, highlighting its moderate basicity. This value can be used in calculations involving the concentration of hydroxide ions produced in a solution of methylamine.
If you added less than the amount needed in part (b) of K2SO3, what would be the limiting reactant? If you added more than the amount needed in part (b) of K2SO3, what would be the limiting reactant? Which situation would create the most SO2 gas?excess HClexcess K2SO3 excess H2Oexcess KClperfectly matched amounts of HCl and K2SO3
The equilibrium constant ( K_b ) for the reaction of methylamine (CH₃NH₂) with water to form its conjugate acid (CH₃NH₃⁺) and hydroxide ions (OH⁻) can be expressed as: [ K_b = \frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]} ] This reaction represents the base dissociation of methylamine in aqueous solution, where it acts as a weak base. The value of ( K_b ) can be determined experimentally or calculated using the relationship between ( K_w ), ( K_a ), and ( K_b ) if the ( K_a ) for its conjugate acid is known.
Kb = [CH3NH3 +] [OH-] / [CH3NH2]
The base dissociation constant (Kb) for methylamine (CH3NH2) in water is a measure of its ability to accept a proton (H+) from water, forming CH3NH3+ and hydroxide ions (OH-). The equilibrium expression for this reaction is given by Kb = [CH3NH3+][OH-] / [CH3NH2]. For methylamine, Kb is approximately 4.2 × 10^-4 at 25°C, indicating its relatively weak basicity compared to stronger bases.
6.6 x 10-9
The base dissociation constant (Kb) for methylamine (CH3NH2) can be determined from its equilibrium reaction with water, where CH3NH2 accepts a proton to form CH3NH3+ and hydroxide ions (OH-). The Kb value indicates the strength of CH3NH2 as a base, reflecting its ability to generate OH- in solution. For methylamine, Kb is approximately 4.2 × 10^-4, highlighting its moderate basicity. This value can be used in calculations involving the concentration of hydroxide ions produced in a solution of methylamine.
2NaOHaq + 2HClaq --> 2NaClaq + H2Ol is the perfect balanced equatiion,except the solubility (aq) of NaCl, so it is notNaCls but NaClaq
If you added less than the amount needed in part (b) of K2SO3, what would be the limiting reactant? If you added more than the amount needed in part (b) of K2SO3, what would be the limiting reactant? Which situation would create the most SO2 gas?excess HClexcess K2SO3 excess H2Oexcess KClperfectly matched amounts of HCl and K2SO3
The equilibrium constant ( K_b ) for the reaction of methylamine (CH₃NH₂) with water to form its conjugate acid (CH₃NH₃⁺) and hydroxide ions (OH⁻) can be expressed as: [ K_b = \frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]} ] This reaction represents the base dissociation of methylamine in aqueous solution, where it acts as a weak base. The value of ( K_b ) can be determined experimentally or calculated using the relationship between ( K_w ), ( K_a ), and ( K_b ) if the ( K_a ) for its conjugate acid is known.
76 plus 54 plus 92 plus 88 plus 76 plus 88 plus 75 plus 93 plus 92 plus 68 plus 88 plus 76 plus 76 plus 88 plus 80 plus 70 plus 88plus 72 equal 1,440
The answer is 672.
27x3+6=87.
132
It is 77