The logarithm of the octanol/water partition coefficient (log P) of boswellia serrata has been reported to be around 7.5. The pKa value of boswellic acid, a major compound found in boswellia serrata, is around 4.8.
The partition coefficient of salicylic acid is approximately 2.29 at a pH of 7.4.
The partition coefficient of paracetamol is reported to be around 0.36 at pH 7.4.
All three isomers are very weak acids, pKa values varying from 10.26 (o- and p-cresol) to 10.09 (for m-cresol). This means that 1.00 M (standard) solutions in water have pH values of 5.13 to 5.05 (at 25oC).
p = -log[H+] = 12.4
Using the compound interest formula A = P(1 + r/n)^(nt), where A is the final amount, P is the principal amount, r is the interest rate, n is the number of times interest is compounded per year, and t is the number of years, we can solve for t when A = 4000, P = 2000, r = 0.06, and n = 1. Plugging these values in, we get: 4000 = 2000(1 + 0.06/1)^(1t) 2 = (1 + 0.06/1)^(1t) 2 = (1.06)^t Taking the logarithm of both sides, we can solve for t: log 2 = t log 1.06 t = log 2 / log 1.06 Using a calculator, we find that t is approximately 11.90. Therefore, it would take approximately 12 years to double the initial amount of 2000 at a 6 percent interest rate compounded annually.
Ka = [H+][A-]/[HA] [H+] = Ka * [HA]/[A-] pH = pKa - log [HA]/[A-] pH = 4.7 - log (2) = about 4.4 Technically I should have taken dissociation of the acid into account when computing the acetate ion concentration, but at these concentrations it's going to be negligible compared to that from sodium acetate.
The pKa value of p-methoxyphenol is approximately 10.0. This means that it is a weak acid. The pKa value affects the chemical properties of p-methoxyphenol by determining its ability to donate a proton in a chemical reaction. A lower pKa value indicates a stronger acid, while a higher pKa value indicates a weaker acid. In the case of p-methoxyphenol, its pKa value of 10.0 suggests that it is a relatively weak acid compared to stronger acids with lower pKa values.
Yes. Take any rational number p. Let a = any number that is not a power of 10, so that log(a) is irrational. and let b = p/log(a). log(a) is irrational so 1/log(a) must be irrational. That is, both log(a) and log(b) are irrational. But log(a)*log(b) = log(a)*[p/log(a)] = p which is rational. In the above case all logs are to base 10, but any other base can be used.
From this salt the benzoate ion C6H5-COO- is a base ( the other part Na+ is neutral).This base has a pKB value of 9.80 (benzoate)The pKacid value of its conjugated benzoic acid ( C6H5-COOH) however ispKbenzoic-acid = 4.20 = pKa(which is (not surprisingly) equal to 14.0-pKbase = 14.0-9.80)
Some say that pH stands for the "power of hydronium," (or hydrogen) but this is disputed. Other interpretations include "percentage of hydronium" or "potential of hydronium," with hydronium interchangable with "hydrogen." The "p" could also be a constant that means "the negative log of" as in pKa.
When X is 1, regardless of the base p.
the right way >:P
You have to use logarithms (logs).Here are a few handy tools:If [ C = D ], then [ log(C) = log(D) ]log(AB) = log(A) + log(B)log(A/B) = log(A) - log(B)log(Np) = p times log(N)
They should have a log P value of 2.6.
slightly log P of 1.35 is barely cutting it
pH is defined as: pH = -log[H+] where '-log' is the negative of the mathematical function log base 10, 'log10' and [H+] is the concentration of hydrogen ions or hydronium (H3O+) in mol dm-3 If you can work out the concentration of H+ ions in aqueous solution, put it into the pH equation to work out pH. It's useful to know that 'p' in physical chemistry generally means '-log', so pKa is equal to -logKa.
p = -log H= concentration of hydrogen in solution (H+) therefore, pH= -log [H+] or [H+] = 10-pH