When heating iron (Fe) and sulfur (S) together, a chemical reaction occurs to form iron sulfide (FeS). This reaction is exothermic and produces a black solid product. The iron sulfide formed can be observed as a black solid residue after the reaction is completed.
Copper (Cu) and iron (Fe) in their solid forms (Cu(s) and Fe(s)) are considered elements, as they consist of only one type of atom each. When combined, they do not form a compound unless they undergo a chemical reaction to create a new substance. Therefore, Cu(s) plus Fe(s) remains a mixture of elements rather than a compound.
The chemical reaction is:Pb(NO3)2 + Fe SO4 = PbSO4(s) + Fe(NO3)2
Fe and S are chemical elements commonly used in various industries. Fe (iron) is used in the production of steel, construction, and manufacturing of vehicles and machinery. S (sulfur) is used in the production of fertilizers, pharmaceuticals, and chemicals.
To determine the mole ratio of Fe₂S₃ to O₂ in a balanced chemical reaction, you need to look at the coefficients in the balanced equation. For example, if the balanced equation is 4 Fe₂S₃ + 12 O₂ → 8 Fe₂O₃ + 6 SO₂, the mole ratio of Fe₂S₃ to O₂ would be 4:12, which simplifies to 1:3. Therefore, the mole ratio of Fe₂S₃ to O₂ is 1:3.
Fe(s) + 3AgNO3 ==> Fe(NO3)3 + 3Ag(s)
When heating steel wool (Fe) with S8, the ionic equation can be represented as Fe(s) + S8(s) -> FeS(s), where iron reacts with sulfur to form iron sulfide.
ordinary mixing is a physical change but when you get to heat them products are formed and it is a chemical change.
Fe + S -------> Fe + S . 8 8 8 8
In laboratory settings, you can make react a mixture of powdered sulphurand iron filings by heating. The end product is Ferrous Sulfide;Fe + S ----> FeSIron sulfides in nature are Pyrite and Marcasitewhose formula is; FeS2 .
+3 for Fe -2 for S
Fe + S = FeS
The oxidation half-reaction is: Fe => Fe+3 + 3e-, and the reduction half-reaction is: F2 + 2e- => 2 F-1. For a complete equation, the oxidation half-reaction as written must be multiplied by 2 and added to the reduction half-reaction as written multiplied by 3 to result in an overall reaction of 2 Fe + 3 F2 = 2 FeF3.
There are two elements in FeS: iron (Fe) and sulfur (S).
Fesub2 S
The empirical formula for the ionic compound formed by Fe and S is Fe2S3, because iron (Fe) typically forms ions with a +3 charge, and sulfur (S) typically forms ions with a -2 charge. This results in a compound with a 2:3 ratio of Fe to S atoms.
The balanced chemical equation for the reaction of iron (Fe) with copper (Cu) is: Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
Copper (Cu) and iron (Fe) in their solid forms (Cu(s) and Fe(s)) are considered elements, as they consist of only one type of atom each. When combined, they do not form a compound unless they undergo a chemical reaction to create a new substance. Therefore, Cu(s) plus Fe(s) remains a mixture of elements rather than a compound.