Actually the base eg OH group attacks on the alpha Hydrogen atom thus releasing the carbanion and itself forming water. The carbanion further reacts with another aldehyde molecule forming methoxide ion which reacts with water to form aldol product and releases the OH group.
Aldol condensation is the reaction of two aldehydes in the presence of a basic catalyst. The aldol condensation leads to an aldol product, in which an hydroxyl group is attached to the beta carbon of an aldehyde. Claisen condensation is similar to aldol condensation, but is involves two esters instead of two aldehydes. The product of a Claisen condensation is a beta-keto-ester, a compound characterized by an ester with its alpha carbon being a ketone.
well based on my studies two compounds are produced, viz: ethanedial and methanal
When benzaldehyde reacts with ethanal, an Aldol condensation reaction takes place. The benzaldehyde acts as the electrophile and the ethanal acts as the nucleophile. The reaction forms a beta-hydroxy aldehyde intermediate, which can then undergo dehydration to form an alpha,beta-unsaturated aldehyde.
To modify the Aldol Synthesis of Dibenzalacetone to produce benzalacetone instead, you would use one equivalent of benzaldehyde as the aldehyde component, along with one equivalent of acetone as the ketone component. This would result in the formation of benzalacetone through the aldol condensation reaction.
When ethanal (acetaldehyde) is heated with dilute NaOH solutions, it undergoes an aldol condensation reaction, ultimately leading to the formation of β-hydroxybutyraldehyde. This compound can further dehydrate to yield crotonaldehyde (2-butenal) as the final product. The reaction is a classic example of the aldol reaction, where two molecules of ethanal react under basic conditions.
Only those aldehydes may undergo the aldol condensation which have the alpha hydrogen (hydrogen at carbon adjacent to carbonyl carbon) in benzaldehyde alpha carbon is not present so it can not undergoes the aldol condensation.
Compounds which have CH3CO- group or compounds that can be converted to CH3CO- group undergo aldol condensation. 1-propanol doesn't undergo aldol condensation. However 2-propanol undergoes aldol condensation.
Aldol condensation is the reaction of two aldehydes in the presence of a basic catalyst. The aldol condensation leads to an aldol product, in which an hydroxyl group is attached to the beta carbon of an aldehyde. Claisen condensation is similar to aldol condensation, but is involves two esters instead of two aldehydes. The product of a Claisen condensation is a beta-keto-ester, a compound characterized by an ester with its alpha carbon being a ketone.
Yes, 2-hydroxy-2-methyl pentanal can be formed as a product of aldol condensation. Aldol condensation typically involves the reaction between an aldehyde or ketone with an enolate ion, leading to the formation of a beta-hydroxy aldehyde or ketone. In this case, the given compound fits the description of a beta-hydroxy aldehyde, which can be a product of aldol condensation.
Aldol condensation is the reaction of two aldehydes in the presence of a basic catalyst. The aldol condensation leads to an aldol product, in which an hydroxyl group is attached to the beta carbon of an aldehyde. Claisen condensation is similar to aldol condensation, but is involves two esters instead of two aldehydes. The product of a Claisen condensation is a beta-keto-ester, a compound characterized by an ester with its alpha carbon being a ketone.
All condensation reactions proceed with formation of water (H2O). If you look at the reaction mechanism for Aldol condensation, you will observe that water is formed as an end-product of the reaction.
Acetophenone can undergo aldol condensation, where it can form a beta-hydroxy ketone through reaction with a strong base. This reaction involves the nucleophilic addition of an enolate ion formed from acetophenone to another acetophenone molecule, followed by dehydration to form the beta-hydroxy ketone product.
Not really because aldol condensation of 2 CH3CHO would be a major competing process.
crotonaldhyde CH3-CH=CH-CHO
ethyl acetate undergoes aldol condensation with benzaldehyde. in the aldol product the aceto group undergoes enolisation. Urea attacks through 1,4 addition.
The use of sodium bicarbonate in an aldol condensation reaction helps to neutralize any acidic byproducts that may form during the reaction. This can prevent side reactions and improve the yield of the desired product.
well based on my studies two compounds are produced, viz: ethanedial and methanal