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To find the Celsius temperature of a gas with an average kinetic energy of 3866 joules, we can use the formula for the average kinetic energy of a gas, which is ( KE = \frac{3}{2} nRT ). For 1 mole of gas (n = 1), this simplifies to ( KE = \frac{3}{2} RT ). Rearranging for temperature (T) gives ( T = \frac{2 \times KE}{3R} ). Using the gas constant ( R \approx 8.314 , J/(mol \cdot K) ), we find ( T \approx \frac{2 \times 3866}{3 \times 8.314} \approx 310.5 , K ). Converting this to Celsius gives ( T_{C} \approx 310.5 - 273.15 \approx 37.4 , °C ).

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6d ago

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