The KVAR will be 1249.75, the power factor is .7.
KVAR = sqrt [ KVA^2 - kW^2 ]
The formula is that kW^2 + kVAR^2 equals kVA^2 or if you prefer, the kW and the kVAR are the two sides of a right angled triangle and the kVA is the hypotenuse. So here you have a 3-4-5 triangle times 140, in other words 420-560-700, and the kVAR is 420.
It depends on the power factor, which depends on the reactance of the load.For a typical power factor of 0.92, 150 KVAR translates to 383 KVA, which translates to 352 KW.Power factor is the cosine of the phase angle (theta) between voltage and current. KVA times cosine (theta) is KW, while KVA times sine (theta) is KVAR.
To convert AC tonnage to kVA and kW, use the following formulas: For kVA: kVA = (tonnage x 3.517) For kW: kW = (tonnage x 3.517 x power factor). Remember to consider the power factor of the system when converting from tonnage to kVA and kW.
To convert 2 kW to kVA in single phase, you need to know the power factor. If we assume a power factor of 0.8 (common for many single-phase loads), the conversion formula is kVA = kW / power factor. Therefore, for 2 kW at a power factor of 0.8, the result would be 2 kVA / 0.8 = 2.5 kVA.
There are 1,000 watts (W) in a kilowatt (kW) and 1,000 volt-amps (VA) in a kilovolt-ampere (kVA). Therefore, 1 kVA is equal to 1 kW.
The same way, as you convert Appels to Carrots ........... There is a formula: KVAr = KVA / KW or cos=KW/KVA > Yes, we are treating KW, KVA, & KVAr as the 3 sides in a 90 deg TRIANGLE ! KW= vertical katede KVAr = horizontal katede KVA = hypotenuse
kvar can be calculated as follows the a product KVA andt the sine of the angle between the KVA and KW.
kvar can be calculated as follows the a product KVA andt the sine of the angle between the KVA and KW.
kV is kilovolts, kW is kilowatts, kVA is kilovolt amps and kVAR is kilovolt-amps reactive. A common formula is kVA-squared = kW-squared + kVAR-squared.
The formula is that kW^2 + kVAR^2 equals kVA^2 or if you prefer, the kW and the kVAR are the two sides of a right angled triangle and the kVA is the hypotenuse. So here you have a 3-4-5 triangle times 140, in other words 420-560-700, and the kVAR is 420.
For normal power factors (pf=80%), you have 0.8 kW for every kva. In general however, kW = pf x kVA. Where pf is the power factor, it is the cosine of the angular difference between the voltage and the current of a circuit in alternating current circuits.
It depends on the power factor, which depends on the reactance of the load.For a typical power factor of 0.92, 150 KVAR translates to 383 KVA, which translates to 352 KW.Power factor is the cosine of the phase angle (theta) between voltage and current. KVA times cosine (theta) is KW, while KVA times sine (theta) is KVAR.
Kilowatts (kW) measure real power, which is the actual power consumed by electrical devices to perform work. Kilovars (kVAR), on the other hand, measure reactive power, which is used to maintain the electric and magnetic fields in inductive and capacitive components. The relationship between kW and kVAR is important in understanding power factor, as they combine to define the apparent power (measured in kVA) in an AC circuit, through the equation: ( \text{kVA}^2 = \text{kW}^2 + \text{kVAR}^2 ). A higher kVAR can indicate inefficiencies in a system, requiring correction to optimize power usage.
{| |- | capacitance of the capacitor is mentioned in KVAR. Formula : KVAR = KW*tan@ FOR tan@, First note the power factor & KW without connecting capacitor. The noted power factor is in cos@.Convert the cos@ value in tan@. for ex. If power factor is 0.6, KW = 200 cos@ = 0.6 cos-1 (0.6) = 53.1 tan (53.1) = 1.333 200*1.333 = 266.6 KVAR if you use 266 KVAR capacitor, Then the power factor improves to unity (1.000). |}
When the power factor is leading, the capacitive kVAr is more than the Inductive kVAr and this still has to be supplied by the source. As kVA is the vector sum of kW and kVAr, still for the given kW, you have to produce more kVA. Alternately, for the given kVA, you can only convert partially into useful work. Secondary effects are voltage boost in the system, availability of stored energy to feed the fault in case of a fault, increase in the asymmetrical component of fault current, increasing thus the peak value of the fault current, etc.
Depending upon the connected load ( R, RL, RC or RLC) with a transformer, the power goes ou from a transformer may be of two types: 1. Active Power; measured in kW 2. Reactive Power; measured in kVAR If the rating will be in kW, then kVAR rating would not be accounted but if the rating is in kVA then it is possible for us to calculate the total active and reactive current as well as the powers, at a particular system voltage!
It depends on the power factor of the load, but for a load power factor of 0.7 on a 2000 kVA transformer the real power and reactive power are both 1400 kilo (watts and VAR). So a 1400 kVAR capacitor on the load would restore the power factor to 1, allowing 2000 kW to be drawn instead of only 1400 kW.