To determine the annual kWh for a 60 hp boiler, you would need to know the average hours of operation per year and the efficiency of the boiler. You can use the formula: kWh = hp x 0.7457 x hours of operation x boiler efficiency. This formula takes into account the power factor and converts horsepower to kilowatts.
1 HP = 2446 btu/hr and 1 kWh=3413 btu/hr so 1kWh = 1.413 HP, thus 45kWh x 1.413 = 63.585 HP.
To calculate the energy consumption of a 10 hp motor in kWh, you would need to know the motor's efficiency and the duration it runs. Without this information, it's not possible to provide a precise answer. Horsepower (hp) measures power, while kilowatt-hours (kWh) measure energy consumption over time.
watt denotes the measure of energy consumes per unit time( 1 second). As 1 hp=.746KW so in 24 hours 0.746 KW will be consumed constantly.
Alternative dissolved oxygen scavengers for high-pressure boiler feed water include sulfite, carbohydrazide, and tannin-based products. These chemicals can effectively reduce dissolved oxygen levels in the water to prevent corrosion and damage to the boiler system. It's important to carefully choose the scavenger based on the specific requirements and operating conditions of the boiler.
There are many factors. First of all, there is the temperature of the water. Next, the is the volume of water. Next there is the amount of pressure gradually built up in the boiler. Next you have the amount and speed at which heat is transferred to the water.
1 HP = 2446 btu/hr and 1 kWh=3413 btu/hr so 1kWh = 1.413 HP, thus 45kWh x 1.413 = 63.585 HP.
1hp = 746 watts, so 2hp would be 1492 watts, or almost 1.5 kw kWh does not convert to hp, as kWh has a time component.
1.34 hp (electric)
To calculate the energy consumption of a 10 hp motor in kWh, you would need to know the motor's efficiency and the duration it runs. Without this information, it's not possible to provide a precise answer. Horsepower (hp) measures power, while kilowatt-hours (kWh) measure energy consumption over time.
hp Boiler = (4675 pound of water in an hour / 34.5 ) = (4675 pounds in an hour of steam at 212 oF / 34.5)
if your talking about a generator its not the hp of the engine its the size, rpm, and gearing of the generator motor
1 hp = 746 watts2 hp = 1,492 watts2 hp x 1 hour = 1,492 watt-hours = 1.492 kWh(Note: The "2 hp" rating on the pump refers to the useful output, that is,the water that the pump moves. The '1.492 kWh' calculated is simply theequivalent of 2 hp-hour, expressed in a different unit. The consumptionfrom the electric utility will be more than that, because no machine is100% efficient, that is, a machine's useful output work/energy is alwaysless than the input to it.To calculate the input energy required to operate this pump at full loadfor an hour, divide 1.492 kWh by the efficiency of the pump.)
To calculate the energy consumption of a 15 hp motor operating at full load for one hour in a three-phase system, you can use the formula: Energy (kWh) = Power (hp) × 0.746 (kW/hp) × Time (hours). For a 15 hp motor, this equates to 15 × 0.746 × 1 = 11.19 kWh. Therefore, a 15 hp motor would consume approximately 11.19 units of electricity in one hour.
To calculate the units consumed by a 7.5 hp motor per hour, first convert horsepower to kilowatts (1 hp ≈ 0.746 kW). Thus, a 7.5 hp motor equals approximately 5.59 kW (7.5 hp × 0.746 kW/hp). If the motor runs continuously for one hour, it would consume about 5.59 kilowatt-hours (kWh), which is equivalent to 5.59 units of electricity, since one unit is equal to one kWh.
A 5.8 hp scooter is 60 hp.
1993 evinrude 60 hp weight is 250 lb.
1990 evinrude 60 hp weight is 250 lbs