PdCl2 + 2HNO3 --> Pd(NO3)2 + 2HCl
The balanced equation for Na + HNO3 is: 2Na + 2HNO3 -> 2NaNO3 + H2
1 nh3+ 2o2 >>>>> 1hno3 + 1h2o
The balanced chemical equation for the reaction between copper (Cu) and nitric acid (HNO3) is: 3Cu + 8HNO3 -> 3Cu(NO3)2 + 2NO + 4H2O According to the equation, 8 moles of HNO3 are required to react with 3 moles of Cu. Therefore, to react with 6 moles of Cu, you would need 16 moles of HNO3.
The balanced chemical equation would be K4FeC6N6 + KMnO4 + H2SO4 = KHSO4 + Fe2SO43 + MnSO4 + HNO3 + CO2 + H2O.
The theoretical yield of HNO3 is the maximum amount of nitric acid that can be produced in a chemical reaction based on stoichiometry and assuming 100% yield. It can be calculated by converting the given amount of reactant to moles, using the balanced equation, and then converting moles to mass of HNO3.
The balanced equation for the reaction between HNO3 and NaHCO3 is: 2 HNO3 + NaHCO3 → NaNO3 + H2O + CO2
The balanced chemical equation for the reaction between ammonia (NH3) and nitric acid (HNO3) is: NH3 + HNO3 → NH4NO3
This equation is NaHCO3 + HNO3 => NaNO3 + H2O + CO2 (g).
balanced equation:- AgNO3(aq) + HBr(aq) ----> AgBr(s) + HNO3(aq)
The balanced equation for Na + HNO3 is: 2Na + 2HNO3 -> 2NaNO3 + H2
The equation is 4 Zn + 10 HNO3 -> 4 Zn(NO3)2 + N2O + 5 H2O.
The balanced chemical equation for the dissociation of nitric acid (HNO3) in water is: HNO3(aq) -> H+(aq) + NO3-(aq)
The chemical formula of nitric acid is HNO3.
the balanced symbol equation for nitric acid and sodium hydroxideis as follows :potassium hydroxide + nitric acid → potassium nitrate + water.KOH + HNO3 → KNO3 + H2O
The reaction is:Ag2CO3 + 2 HNO3 = 2 AgNO3 + CO2 + H2O
Sodium dichromate has the chemical formula of Na2Cr2O7. The reaction with HNO3 is balanced as 2 HNO3 + Na2Cr2O7 = H2Cr2O7 + 2 NaNO3.
Nitric acid: HNO3 (acid) Sodium hydroxide: NaOH (base) This is therefore an acid-base reaction. Acid + Base --> Salt + Water Therefore: HNO3 + NaOH --> NaNO3 + H20 Or: Nitric acid + Sodium hydroxide --> Sodium Nitrate + Water