HCl + Al2O3 ----- H2O + AlCl3
H 1 Cl 1 Al 2 O 3 6HCl + Al2O3 --------- 3H2O + 2AlCl3
2Al + 3Cl2 -> 2AlCl3 aluminium reacts with chlorine gas to form aluminium trichloride.
The balanced chemical equation for the reaction between aluminum and chlorine to form aluminum chloride is 2Al + 3Cl2 → 2AlCl3. Using the molar masses of aluminum and chlorine, we find that 15.0 g of aluminum is equivalent to 0.56 mol and 20.0 g of chlorine is equivalent to 0.28 mol. Since aluminum and chlorine react in a 2:3 ratio, 0.56 mol of aluminum would require 0.84 mol of chlorine. Therefore, the limiting reactant is chlorine, and the maximum mass of aluminum chloride that can be formed is 59.6 g.
When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -> 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.
The reaction between aluminum bromide and chlorine gas forms aluminum chloride and bromine gas. This is a double displacement reaction where the bromine from aluminum bromide is replaced by chlorine to form new compounds. The balanced chemical equation for this reaction is 2AlBr3 + 3Cl2 → 2AlCl3 + 3Br2.
The balanced chemical equation for this reaction is: 2AlBr3 + 3Cl2 -> 2AlCl3 + 3Br2.
The chemical name for aluminum is aluminum (Al) and for chlorine is chlorine (Cl). When these two elements combine, they form aluminum chloride, which has the chemical formula AlCl3.
The chemical equation is:2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2
The chemical equation is:2 AlBr3 + 3 Cl2 = 2 AlCl3 + 3 Br2
2Al + 3Cl2 -> 2AlCl3 aluminium reacts with chlorine gas to form aluminium trichloride.
The correct balanced formula for aluminum chloride is AlCl3. This formula indicates that aluminum forms 1 ion and chlorine forms 3 ions to balance the charges.
The balanced chemical equation for the reaction between aluminum and chlorine to form aluminum chloride is 2Al + 3Cl2 → 2AlCl3. Using the molar masses of aluminum and chlorine, we find that 15.0 g of aluminum is equivalent to 0.56 mol and 20.0 g of chlorine is equivalent to 0.28 mol. Since aluminum and chlorine react in a 2:3 ratio, 0.56 mol of aluminum would require 0.84 mol of chlorine. Therefore, the limiting reactant is chlorine, and the maximum mass of aluminum chloride that can be formed is 59.6 g.
When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -> 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.
The reaction between aluminum bromide and chlorine gas forms aluminum chloride and bromine gas. This is a double displacement reaction where the bromine from aluminum bromide is replaced by chlorine to form new compounds. The balanced chemical equation for this reaction is 2AlBr3 + 3Cl2 → 2AlCl3 + 3Br2.
The balanced chemical equation for this reaction is: 2AlBr3 + 3Cl2 -> 2AlCl3 + 3Br2.
Aluminum bromide (AlBr3) + Chlorine (Cl2) → Aluminum chloride (AlCl3) + Bromine (Br2)
Aluminum chloride is a compound composed of aluminum and chlorine atoms. Its chemical formula is AlCl3, indicating that each molecule contains one aluminum atom and three chlorine atoms joined together.
The compound alcl3 is formed by combining aluminum and chlorine gas. This is what forms aluminum chloride which is an inorganic compound.