answersLogoWhite

0

What else can I help you with?

Related Questions

What is the mass of an ice cube with 1 cm sides?

The density of ice is approximately 0.92 g/cm³. The volume of the ice cube with 1 cm sides is 1 cm³. Therefore, the mass of the ice cube is 0.92 grams.


What is the capacity of 5cm cube in milliliters?

5 cm cube = 125 cubic cm = 125 millilitres.


What is the capacity of a cube with 10 cm sides?

It is: 10*10*10 = 1000 cubic cm


An ice cube is how many cubic cm?

depends on the tray, genius.


What type of liquid affects how fast ice cube will melt?

The type of liquid affects how fast an ice cube will melt due to its thermal conductivity and specific heat capacity. Some liquids, like water, have high thermal conductivity and specific heat capacity, leading to faster melting of the ice cube. Other liquids, like oil, have lower thermal conductivity and specific heat capacity, resulting in slower melting of the ice cube.


A cube has a volume of 125 cm cubed but a capacity of 0 ml how is this possible?

It is possible if the cube is solid all the way through.


What is the capacity of water in an ice cube?

The same as the container that's used to hold the water while it freezes ! An ice-cube can be as small as 1 inch square - or hundreds of feet !


What is the capacity of a 5 cm cube?

If the cube has 5 cm on each side, the volume will be 5 x 5 x 5 = 125 cubic centimeters (or 1/8 cubic decimeter, or 1/8 of a liter).


What is the capacity of a cube with a side length of 6 cm?

Since the formula for volume of a cube is s to the 3rd power, the answer would be 6 to the 3rd power, which equals 216


The length of the edge of a cube is cube root of 6 cm Find the volume of the cube?

In order to find the volume of the cube you multiply length * width * height which is cube root of 6 cm * cube root of 6 cm * cube root of 6 cm = 6 cubic cm


What part of an ice floats on water?

Let V be the volume of the ice cube and U be the volume of the cube immersed in water density of water at 4oC = 0.998 g/cm³ density of ice at 0oC = 0.917 g/cm³ Weight of the ice cube = volume * density * g = 0.917*V*g [N] Buoyancy on the ice cube = volume * density * g = 0.988*U*g [N] Apply Newton's 3rd Law of Motion to the floating ice cube: 0.917*V*g = 0.988*U*g U/V = 0.928 = 92.8% Hence, 92.8% of the ice cube is immersed in water, or 7.2% of the ice cube is above water. The answer in percent can be converted to a fraction as follows: 7.2/100. =========================


An ice cube measures 7 cm on a side and floats in water 0.7 cm extends above water level If you shaved off the 0.7 cm part how many cm of the remaining ice would extend above water level?

0.63cm