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The formula for barium sulfide is BaS. The gram Atomic Mass of barium is 137.33 and the gram atomic mass of sulfur is 32.06. Therefore, the mass percent of barium in barium sulfide is 100[137.33/(137.33 + 32.06)] or 81.073 %. (Five significant digits are justified even though the value for sulfur has only four significant digits, because the only use made of the value for sulfur in the calculation is to add it to a number with more significant digits.)

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