C3H7OH + (9/2)O2 = 3CO2 + 4H2O =>
2C3H7OH + 9O2 = 6CO2 + 8H2O Done!!!!!
Complete combustion of a hydrocarbon yields carbon dioxide & water; incomplete combustion yields carbon monoxide & water. By having excess oxygen you have enough oxygen to ensure complete combustion. For example the combustion of methane (CH4):complete combustion: CH4 + 2O2 --> CO2 + 2H2Oincomplete combustion: CH4 + 1.5O2 --> CO + 2H2OAs you can see you need a 1/2 mole less of oxygen for the incomplete combustion of methane. So as long as you have twice the amount (in terms of moles) of oxygen as methane you will ensure complete combustion. So anything in excess of that will also ensure complete combustion.
The main products of complete combustion are carbon dioxide (CO2) and water (H2O).
You think probable to molar heat, expressed in J/mol.
Yes, more oxygen is used in incomplete combustion compared to complete combustion because incomplete combustion results in the partial burning of the fuel, leading to the formation of more byproducts like carbon monoxide and soot. This requires additional oxygen to combine with these byproducts, using up more oxygen overall.
In all combustion reactions (other than H2 with O2) CO2(g) and H2O(g) will be produced. CO would NOT be produced, as we are talking about COMPLETE combustion. Why can't the products be in a form of an oxide and a compound gas?
The balanced equation for the complete combustion reaction is 2 C3H7OH + 9 O2 -> 6 CO2 + 4 H2O; therefore, the coefficient for oxygen is 9. If fractional coefficients are allowed, the equation can be written with only one mole of C3H7OH; in that instance the coefficient for oxygen would be 9/2.
Complete combustion : 2C3H8O + 9O2 --> 6CO2 + 8H2O Incomplete combustion : C3H8O + 3O2 --> 3CO + 4H2O
C3H7OH C3H7OH
If the combustion is complete, carbon dioxide and water.
C3H7OH
The resulting products of the complete combustion are water and carbon dioxide.
Yes, C3H7OH, which is also known as isopropyl alcohol or rubbing alcohol, is soluble in water. This is because it forms hydrogen bonds with water molecules, allowing it to dissolve in water.
Complete combustion will result in the production of CO2 and H2O.
Complete combustion is very hard to obtain, unless you have nearly perfect conditions and little cause for error.
The main products of complete combustion are carbon dioxide (CO2) and water (H2O).
Complete combustion of a hydrocarbon yields carbon dioxide & water; incomplete combustion yields carbon monoxide & water. By having excess oxygen you have enough oxygen to ensure complete combustion. For example the combustion of methane (CH4):complete combustion: CH4 + 2O2 --> CO2 + 2H2Oincomplete combustion: CH4 + 1.5O2 --> CO + 2H2OAs you can see you need a 1/2 mole less of oxygen for the incomplete combustion of methane. So as long as you have twice the amount (in terms of moles) of oxygen as methane you will ensure complete combustion. So anything in excess of that will also ensure complete combustion.
The general equation for the complete combustion of a hydrocarbon fuel such as fossil fuels is: hydrocarbon + oxygen → carbon dioxide + water For example, the complete combustion of methane (CH4) would be: CH4 + 2O2 → CO2 + 2H2O.