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[Kr]5s1 would be the noble gas electron configuration for Rb.

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What is the noble gas configuration of rb?

[Kr] 5s1


What does not have a noble gas configuration Na Rb O2 Br Ca Al3 S2?

Na, Rb, Al3+, and S2- do not have a noble gas configuration as they do not have the complete outer shell of electrons like a noble gas. O2, Br, Ca, and O2- have noble gas configurations as they either have a complete outer shell of electrons or have gained/lost electrons to achieve a stable noble gas configuration.


What noble gas configurations is Rb likely to adopt in reactions when it form ions?

Rb is likely to adopt a noble gas configuration of [Kr] when it forms ions. This means it will lose one electron to achieve a stable octet configuration, similar to the nearest noble gas element, krypton.


What is the Noble gas notation of rubidium?

Rubidium has an atomic number of 37, making it an alkali metal. This means that its last shell is an s with only one electron. The full notation is [Kr] 5s1.


How many electrons do Rb have?

Rubidium (Rb) has a +1 ion, will have the same electron configuration as krypton (Kr) because the +1 status means it has lost an electron. The configuration is written 1s22s22p63s23p64s23d104p6.


What is the shorthand configuration of Rb and what ion will it form?

google it


What is the electron configuration for Rb plus 1?

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 Rb+1 or Kr


What is the configuration of Rb?

1s2 2s2p6 3s2p6d10 4s2p6 5s1


What is electronic configuration of rubidium?

Rb has the electronic config. of = [Kr] 5s1


What is the Electronic configuration of Rb?

1s2 2s2p6 3s2p6d10 4s2p6 5s1


What is the electron configuration for element kr?

The lowest atomic number ion is Se^2-. The highest atomic number ion is Sr^2+. The ones in the middle are NOT Br^- or Rb^+. However, I do not know what the correct answer for those two is.


How many 5s electrons are in Rb sublevel?

In the Rb atom, the electron configuration is [Kr]5s^1. This means there is 1 electron in the 5s sublevel of the Rb atom.