2 FeI3 ===> 2 Fe + 3 I2
The balanced chemical equation for the reaction of oxygen with iron to form iron (III) oxide is: 4 Fe + 3 O₂ → 2 Fe₂O₃. This equation shows that four moles of iron react with three moles of oxygen to produce two moles of iron (III) oxide.
This is iron(III) hydroxide.
The formula for iron (III) iodide is FeI3, where iron is in the +3 oxidation state and iodine is in the -1 oxidation state.
The balanced equation for the reaction of solid iron with gaseous oxygen to form solid iron(III) oxide is: 4 Fe (s) + 3 O₂ (g) → 2 Fe₂O₃ (s). This equation indicates that four moles of iron react with three moles of oxygen to produce two moles of iron(III) oxide.
4Fe(s) + 3O2(g) ===> 2Fe2O3(s)
Iron (III) Iodide.
Iron(II) iodide = FeI2 Iron(III) iodide = FeI3
iron diodide
Depends on if you have iron (II) iodide or iron (III) iodide. iron (II) iodide is FeI2, while iron (III) iodide is FeI3.
A chemical reaction occurs where iron III iodide is formed and potassium nitrate is produced as a byproduct. The balanced chemical equation for this reaction is 2KI + Fe(NO3)3 -> 2KNO3 + FeI3. Iron III iodide is a dark brown solid, whereas potassium nitrate remains in solution.
Common catalysts used in the decomposition of hydrogen peroxide include manganese dioxide, potassium iodide, and iron(III) chloride.
The correct name for the compound FeCl3 is iron(III) chloride.
Iron(II) Iodide = FeI2 Iron(III) Iodide = FeI3
The equation for the decomposition of iron(III) chlorate is: 2Fe(ClO3)3(s) → 2FeCl3(s) + 3O2(g) + 3ClO2(g)
Iron III iodide and cupric nitrate would react in a double displacement reaction to form iron III nitrate and copper II iodide. The balanced chemical equation for the reaction is: FeI3(aq) + 3Cu(NO3)2(aq) -> Fe(NO3)3(aq) + 3CuI(s)
The chemical formula for the compound formed between iron(III) and iodine is FeI3 (iron(iii) iodide).
the equation for sodium nitrate and copper III iodide can be given below.Cu I 2 +2 Na No3 ->I (NO3)2 + 2NaI. this is the balance reaction for the above.