3CuI2 + 2Fe(NO3)3
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
Nothing happens.
Pb(NO3)2 + 2NaI = PbI2 = 2NaNO3 Lead iodide is a yellow precipitate.
The word equation would be iron reacts with lead nitrate to form iron two nitrate and lead.Or perhaps you meant this?The word equation would be Iron + Lead Nitrate => Iron (II) Nitrate + LeadThe chemical equation would be Fe(s) + Pb(NO3)2 => Fe(NO3)2 + PbI assume you are having problems with the charge the iron nitrate would go into, so here is a link that helps describe how to determine the charges of the ions of transitional metals: http://indiescience.org/basetalk/index.php?topic=13.0
3AgNO3 + FeCl3 ---> 3AgCl + Fe(NO3)3
Silver nitrate plus potassium iodide yields silver iodide plus potassium nitrate.
No, reaction
= Copper(II) chloride + Nitric acid
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
Nothing happens.
AgNO3 + KI ----> AgI(ppts.) + KNO3
The reaction is the following:AgNO3 + KI = KNO3 = AgI(s)
Pb(NO3)2(aq) + 2KI)aq) = 2KNO3(aq)+ PbI2(s) PbI2 is a yellow coloured solid and will precipitate out of the solution.
2AgNO3 + CaI2 >> 2AgI + Ca(NO3)2
Zn2 + Fe3NO3 -> Zn3NO2 + Fe3
Pb(NO3)2 + 2NaI = PbI2 = 2NaNO3 Lead iodide is a yellow precipitate.
FeO+LiNO3------->LiO+FeNO3it is already balanced ..............................