3CuI2 + 2Fe(NO3)3
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
When iron reacts with potassium iodide, it forms potassium iodide. The reaction can be written as 2Fe + 2KI → 2K + 2FeI. Potassium iodide is a salt and is commonly used as a nutritional supplement.
When potassium iodide is mixed with lead nitrate, a double displacement reaction occurs. The products formed are lead iodide and potassium nitrate. Lead iodide is a yellow precipitate that forms during the reaction.
The word equation would be iron reacts with lead nitrate to form iron two nitrate and lead.Or perhaps you meant this?The word equation would be Iron + Lead Nitrate => Iron (II) Nitrate + LeadThe chemical equation would be Fe(s) + Pb(NO3)2 => Fe(NO3)2 + PbI assume you are having problems with the charge the iron nitrate would go into, so here is a link that helps describe how to determine the charges of the ions of transitional metals: http://indiescience.org/basetalk/index.php?topic=13.0
The chemical equation for iron(III) chloride reacting with silver nitrate is: FeCl3 + 3AgNO3 -> Fe(NO3)3 + 3AgCl
Silver nitrate plus potassium iodide yields silver iodide plus potassium nitrate.
= Copper(II) chloride + Nitric acid
Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.
2Na + 2Fe(NO3)3 -> 6NaNO3 + 2Fe
The balanced chemical equation for silver nitrate (AgNO3) plus calcium iodide (CaI2) is: 2AgNO3 + CaI2 -> 2AgI + Ca(NO3)2
When sodium nitrate (NaNO3) reacts with potassium iodide (KI), it forms sodium iodide (NaI) and potassium nitrate (KNO3). This reaction is a double replacement reaction, where the positive ions from each compound switch places. The chemical equation for this reaction is: NaNO3 + KI → NaI + KNO3.
The reaction is the following:AgNO3 + KI = KNO3 = AgI(s)
When iron reacts with potassium iodide, it forms potassium iodide. The reaction can be written as 2Fe + 2KI → 2K + 2FeI. Potassium iodide is a salt and is commonly used as a nutritional supplement.
Yes, this is a displacement reaction. Iron will displace silver in the silver nitrate solution to form iron(II) nitrate and silver metal.
When potassium iodide is mixed with lead nitrate, a double displacement reaction occurs. The products formed are lead iodide and potassium nitrate. Lead iodide is a yellow precipitate that forms during the reaction.
When silver nitrate and potassium iodide are combined, they undergo a double displacement reaction. Silver iodide is formed as a yellow precipitate, while potassium nitrate remains in solution. The balanced chemical equation for this reaction is: AgNO3 + KI -> AgI + KNO3.
The formula for iron reacting with copper(II) nitrate is: Fe + Cu(NO3)2 -> Fe(NO3)2 + Cu. This is a single displacement reaction where iron displaces copper from copper nitrate to form iron(II) nitrate and copper metal.