The distance between the Sun and the Earth is 1 AU (149.597 m km / 93 m miles) whereas the distance between the Sun and Venus is at an average of 0.723 AU (108. 200 m km / 67.625 m miles). So it can be called 72% of the Sun-Earth distance.
-- If your mass is 'm', then your mass is 'm', regardless of whether you're on the earth,2 earth radii out in space, or on the moon. Mass doesn't change.-- On the surface, your distance from the center of the earth is 1 earth radius. Weight isinversely proportional to the square of the distance from the center of the earth, so at adistance of 3 earth radii from the center, your weight is 1/32 = 1/9th of your weight on thesurface. If your mass is 'm' then your weight on the surface is mg = 9.8m newtons, and at3 earth radii from the center it's 1.089m newtons (rounded).
The absolute magnitude of a star is a measure of its true brightness if it were placed at a standard distance of 10 parsecs from Earth. To calculate the absolute magnitude from the apparent magnitude (m) of 6, you would need to know the star's distance. Without this information, we cannot determine the absolute magnitude.
The angle is tan-1(M/E)*(D/R)2 where M is the mass of the earth, E is the mass of the mountain, R is the distance of the plumb bob from the centre of mass of the earth - near enough the earth's radius, D is the distance of the bob from the centre of mass of the mountain. Both M/E and D/R will be small so that the angle will also be small. In that case, the tangent of the angle will be close to the angle itself (measured in radians). So the angle of deflection is approximately (M/E)*(D/R)2 radians.
There are many units for measuring length and distance . S.I units for length and distance is meter (m).
The distance between the Sun and the Earth is 1 AU (149.597 m km / 93 m miles) whereas the distance between the Sun and Venus is at an average of 0.723 AU (108. 200 m km / 67.625 m miles). So it can be called 72% of the Sun-Earth distance.
14 m
No.
Mean Distance from Earth: 3.844x10^8 m Speed of Light (in a vaccum) 3x10^8 m/s T = D/V T = 3.844x10^8 m / 3x10^8 m/s T ~= 1.28 seconds Pleae note that the moon/earth distance varies, thus we used the mean in this equation.
The star cluster, M 35 is about 2800 light years from Earth.
no
No.
from. Special case- "to and fro" the M is omitted in this case.
cristals
-- If your mass is 'm', then your mass is 'm', regardless of whether you're on the earth,2 earth radii out in space, or on the moon. Mass doesn't change.-- On the surface, your distance from the center of the earth is 1 earth radius. Weight isinversely proportional to the square of the distance from the center of the earth, so at adistance of 3 earth radii from the center, your weight is 1/32 = 1/9th of your weight on thesurface. If your mass is 'm' then your weight on the surface is mg = 9.8m newtons, and at3 earth radii from the center it's 1.089m newtons (rounded).
It looks to me likeAcceleration of gravity = G M / R2The 'M' contributing to the acceleration is the 'M' inside the 'R' of interest. If the earth is homogeneous,then the 'M' is proportional to the volume inside the 'R', which varies as R3 .So the acceleration is proportional to [ M / R2 ], in turn proportional to [ R3 / R2 ] = R.Again, that's assuming the earth is homogeneous, which we know it isn't. But for a uniform,homogeneous 'planet', the acceleration of gravity varies directly with the distance from the center.
Lily