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We know its value at a distances of 6378 km from the centre, that is where most of us are. It is an inverse-square force, so to experience 1/145th of the force you have to go to sqrt(145) times further away, which is a distance of 76,800 km.

The force acting on the Moon is 1/3500 of what it is on the Earth's surface, which is why the Moon accelerates towards us at 2.8 mm/sec^2. But that is combined with a sideways velocity of 1 km/sec so it never hits us, it just keeps on going round in circles.

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How much above the surface of earth does the acceleration due to gravity reduces by 36 percent of its value on the surface of earth radius of earth equals 6400 km?

The acceleration due to gravity decreases with distance from the center of the Earth. Using the formula for gravitational acceleration (g) at a distance (r) from the center of the Earth: ( g' = \frac{G \cdot M}{(r+a)^2} ), where a is the radius of the Earth and G is the gravitational constant, you can calculate the distance above the surface of the Earth at which the acceleration due to gravity reduces by 36 percent.


What is the gravitational acceleration of an object on the surface of the earth?

At or near the surface of the earth, the acceleration due to gravity is 32 feet per second per second


What is the numerical number for the gravitational acceleration?

The numerical value for the gravitational acceleration on the surface of Earth is approximately 9.81 m/s^2.


Why is the acceleration due to gravity on the surface of Mars is about one third the acceleration due to gravity on earths surface?

The acceleration due to gravity is lower on Mars compared to Earth because Mars has less mass than Earth, which means it exerts less gravitational pull. This difference in mass causes Mars to have a weaker gravitational field and therefore a lower acceleration due to gravity.


What is the distance from the Earths center to a point outside the Earth where the gravitational acceleration due to the Earth is 1 26 of its value at the Earths surface?

That would have to be at a radius that is sqrt(26) = 5.1 times the Earth's physical radius, or about 32,486 kilometers (20,186 miles) from the center.


Why is gravitational field strength at earth surface 10?

The gravitational field strength at the Earth's surface is approximately 10 N/kg (or 10 m/s^2) due to the mass of the Earth and the distance from its center. This value is a result of the acceleration experienced by objects in free fall near the Earth's surface.


What is the Gravitational Acceleration of Earth?

On or near the surface of the Earth, the acceleration of gravity is9.8 meters (32.2 feet) per second2 .It becomes less as you move away from the surface.(Either up or down!)


Why does a man get hurt when he jumps from a significant height even though newtons universal gravitational law says that height is inversely proportional to acceleration due to gravity?

The difference in gravitational acceleration depends on the distance from the centre of the earth , not the surface. The equation for the new rate of accelration calculated from the surface rate is: > a = k / ( ( d / r )2 ) > where: a = acceleration due to gravity at new position k = surface rate of acceleration ( use 9.82 (m/s)/s ) d = distance from earths centre to new position ( r + height of jump) ( 6376000 metres) r = surface radius ( use 6371000 metres ) > Even if you jump from 5,000 metres the rate of acceleration would be : > 9.8046 (m/s)/s , which is 99.84 % of the rate at the surface


How do you find the weight of an object on earth?

You could weigh it against other objects. If it is not on the surface, multiply its mass by the acceleration of gravity (at that distance) to find its gravitational potential in newtons.


Where do you experience more gravity on earths surface or earths center?

on the surfaceNote:Since the earth's composition is not homogeneous, the gravitational acceleration onthe surface is probably less than what it is some small distance below the surface,but it's certainly greater than at the center.


What is the potential energy dependant upon an objects weight and distance from earths surface?

The potential energy of an object is dependent on its weight and its distance from Earth's surface due to the gravitational force acting on it. The formula for gravitational potential energy is given by PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object from the reference point.


What is the force of gravity on a person or object on the surface of a planet?

The force of gravity on a person or object at the surface of a planet is calculated by the product of the mass of the person or object and the gravitational constant acceleration for the planet. For Earth, the gravitational acceleration is 9.8 m / s^2.