Mg is present in the chloroplast.
Copper (Cu) is the most metallic element among potassium (K), krypton (Kr), iron (Fe), and copper (Cu). It exhibits high metallic properties such as conductivity and luster.
Copper (Cu) and iron (Fe) in their solid forms (Cu(s) and Fe(s)) are considered elements, as they consist of only one type of atom each. When combined, they do not form a compound unless they undergo a chemical reaction to create a new substance. Therefore, Cu(s) plus Fe(s) remains a mixture of elements rather than a compound.
the mineral element found in haemoglobin is iron
In Fe(OH)3 are three different elements:Fe = ironO = oxygenH = hydrogen
To determine the overall voltage of the reaction involving iron (Fe) and copper (Cu), you need to look at the standard reduction potentials for both half-reactions. The reduction potential for Fe³⁺/Fe is approximately -0.77 V, while for Cu²⁺/Cu it is +0.34 V. The overall cell potential can be calculated by subtracting the reduction potential of the anode (Fe) from that of the cathode (Cu), resulting in a voltage of approximately +1.11 V for the reaction.
Copper (Cu) is the most metallic element among potassium (K), krypton (Kr), iron (Fe), and copper (Cu). It exhibits high metallic properties such as conductivity and luster.
Iron (Fe) is the element present in ferric chloride.
Copper (Cu) and iron (Fe) in their solid forms (Cu(s) and Fe(s)) are considered elements, as they consist of only one type of atom each. When combined, they do not form a compound unless they undergo a chemical reaction to create a new substance. Therefore, Cu(s) plus Fe(s) remains a mixture of elements rather than a compound.
A more reactive element displace the less reactive element from a compound.Example: Fe + CuSO4 = Cu + FeSO4
Fe+CuSO4^Cu+FeSO4
the mineral element found in haemoglobin is iron
Fe + Cu(NO3)2 --> Fe(No3)2 + Cu
The balanced chemical equation for the reaction of iron (Fe) with copper (Cu) is: Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
The element that can form a chloride with the general formula of MCl2 is transition metal elements such as copper (Cu), iron (Fe), or zinc (Zn).
In Fe(OH)3 are three different elements:Fe = ironO = oxygenH = hydrogen
To determine the overall voltage of the reaction involving iron (Fe) and copper (Cu), you need to look at the standard reduction potentials for both half-reactions. The reduction potential for Fe³⁺/Fe is approximately -0.77 V, while for Cu²⁺/Cu it is +0.34 V. The overall cell potential can be calculated by subtracting the reduction potential of the anode (Fe) from that of the cathode (Cu), resulting in a voltage of approximately +1.11 V for the reaction.
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