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What coefficient would the O2 have after balancing C3H8 O2 CO2 H2O?
5
What is the equation of the combustion of propane?
A balanced* equation for the burning of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. *Note that the participial form of "balance" is required for proper grammar in this sentence.
When propane burns in oxygen it forms carbon dioxide and water write the balanced equation?
The balanced chemical equation for the combustion of propane (C3H8) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
Solve C3H8 plus 5 O2 --- 3 CO2 plus 4 H2O?
The balanced chemical equation is C3H8 + 5 O2 ⟶ 3 CO2 + 4 H2O. This means that when one molecule of propane (C3H8) reacts with five molecules of oxygen (O2), it produces three molecules of carbon dioxide (CO2) and four molecules of water (H2O).
Is it likely that the equation C3H8 plus 5 02 - 3 CO2 plus 4 H2O represents the reaction mechanism for the cumbustion of propane?
No, the equation you provided is not balanced. The correct balanced equation for the combustion of propane is C3H8 + 5 O2 → 3 CO2 + 4 H2O. The equation you provided appears to have a typographical error.
What coefficient would the O2 have after balancing C3H8 O2 CO2 H2O?
5
What coefficient would O2 have after balancing C3H8 O2 CO2 H2O?
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
What is c3h8 o2--co2 h2o balanced?
The balanced chemical equation for the combustion of propane is:C3H8 + 5O2 --> 3CO2 + 4H2O
What is the equation for propane combustion?
C3H8 (g) + 5O2 (g) --> 3CO2 (g) + 4H2O (g) is the chemical equation for the combustion of propane.
What is the equation of the combustion of propane?
A balanced* equation for the burning of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. *Note that the participial form of "balance" is required for proper grammar in this sentence.
What is the chemical equation for propane grill?
The chemical equation for burning propane in a grill is: C3H8 + 5 O2 → 3 CO2 + 4 H2O. This equation represents the combustion of propane, where propane (C3H8) reacts with oxygen (O2) to produce carbon dioxide (CO2) and water vapor (H2O) as products.
How many grams of O2 are needed to completely burn 51.6 g of C3H8?
The balanced chemical equation for the combustion of propane (C3H8) is 1 C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This means 5 moles of O2 are required for every 1 mole of C3H8. Calculate the moles of C3H8 in 51.6 g, then use the mole ratio to find the moles of O2 needed. Finally, convert the moles of O2 to grams.
What is the total number of moles of O2(g) required for the complete combustion of 1.5 moles of C3H8(g)?
The balanced chemical equation for the complete combustion of C3H8 is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O This means that 1 mole of C3H8 requires 5 moles of O2. Therefore, 1.5 moles of C3H8 will require 5 * 1.5 = 7.5 moles of O2 for complete combustion.
When propane gas is burned with oxygen the products are carbon dioxide and water write an unbalanced formula equation for the reaction?
C3H8 + O2 ---------> CO2 + H2O UNBALANCED C3H8 + 5O2 ---------> 3CO2 + 4H2O BALANCED
IS C3H8 plus 5O2?
The chemical equation C3H8 + 5O2 -> 3CO2 + 4H2O represents the combustion of propane (C3H8) with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O).
When propane burns in oxygen it forms carbon dioxide and water write the balanced equation?
The balanced chemical equation for the combustion of propane (C3H8) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
What is the chemical reaction Propane burns in oxygen to produce carbon dioxide and steam.?
Study island answer: C3H8 + 5O2 3CO2 + 4H2O
