2(c3h8o)+9o2 => 8h2o+6co2
5
A balanced* equation for the burning of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. *Note that the participial form of "balance" is required for proper grammar in this sentence.
The balanced chemical equation for the combustion of propane (C3H8) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
The balanced chemical equation is C3H8 + 5 O2 ⟶ 3 CO2 + 4 H2O. This means that when one molecule of propane (C3H8) reacts with five molecules of oxygen (O2), it produces three molecules of carbon dioxide (CO2) and four molecules of water (H2O).
No, the equation you provided is not balanced. The correct balanced equation for the combustion of propane is C3H8 + 5 O2 → 3 CO2 + 4 H2O. The equation you provided appears to have a typographical error.
5
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
The balanced chemical equation for the combustion of propane is:C3H8 + 5O2 --> 3CO2 + 4H2O
C3H8 (g) + 5O2 (g) --> 3CO2 (g) + 4H2O (g) is the chemical equation for the combustion of propane.
A balanced* equation for the burning of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. *Note that the participial form of "balance" is required for proper grammar in this sentence.
The chemical equation for burning propane in a grill is: C3H8 + 5 O2 → 3 CO2 + 4 H2O. This equation represents the combustion of propane, where propane (C3H8) reacts with oxygen (O2) to produce carbon dioxide (CO2) and water vapor (H2O) as products.
The balanced chemical equation for the combustion of propane (C3H8) is 1 C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This means 5 moles of O2 are required for every 1 mole of C3H8. Calculate the moles of C3H8 in 51.6 g, then use the mole ratio to find the moles of O2 needed. Finally, convert the moles of O2 to grams.
The balanced chemical equation for the complete combustion of C3H8 is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O This means that 1 mole of C3H8 requires 5 moles of O2. Therefore, 1.5 moles of C3H8 will require 5 * 1.5 = 7.5 moles of O2 for complete combustion.
C3H8 + O2 ---------> CO2 + H2O UNBALANCED C3H8 + 5O2 ---------> 3CO2 + 4H2O BALANCED
The chemical equation C3H8 + 5O2 -> 3CO2 + 4H2O represents the combustion of propane (C3H8) with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O).
The balanced chemical equation for the combustion of propane (C3H8) with oxygen (O2) to form carbon dioxide (CO2) and water (H2O) is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O
Study island answer: C3H8 + 5O2 3CO2 + 4H2O