I find amps by measuring with a 'clamp-on' ammeter. I use this information particularly to evaluate the performance of deep well pumps. If you are looking to determine amperage using known values such as Voltage, Resistance, or Power {Wattage} you will need to use "Ohm's Law". It's the base formula from which most all other formulas regarding electricity extrapolate it's functions from.
Ohm's Law:
E = I [X] R
Where:
E=Voltage or EMF [electro motive force] in Volts or "V"
I=Current in Ampere as "A" or Amps,
R=Resistance in Ohm's as "R" or the Omega symbol
From thew known characteristics of E, I, and R another formula of Ohm's law can be used to determine power using two known values.
Ohm's Law Power Formula:
P = I [X] R
Where:
P=Power in Wattage/Watts as "W"
I=Amp
E=Volts
Examples:
You have a portable car heater {a heating element is just a large resistor for simplicity} and the specifications on its label says he device is a 12 volt appliance that uses 60 Watts of power You are asked to determine what size wire will be needed and the total resistance of the circuit.*
Wire is sized for the amount of current ** it will be required to handle giving as little resistance {i.e. heat} as possible, but not over sized wasting the customers or your own money. Using the given values for E and P we can determine I.
If,
P = I X E then,
60Watts = I {Amps} [X] 12 Volts so,
60 = {I} [X] 12 or,
{I} = 60/12 therefore,
{I} = 5 Amps
As a construction electrician we seldom are required to calculate for anything smaller than 14 guage wire {rated at 15 amps per code} so I am only guessing at 5 amps but I'm sure it is close to 22-24 AWG seeing 18 is good for 14 amps in fixture wiring.
Then:
If,
E-I x R then,
12Volts = 5Amps {from above} [X] R so,
12 = 5 X {R} therefore,
R = 12/5 therefore,
R = 2.5Ohm's
Thus:
The device is a 12 Volt heater that uses 60 Watts of power that allows 5 amperes of current through the circuit that produces 2.5 Ohm's of resistance requiring a min. of 22 AWG wire for the network. .......or...........
Go down to the hardware store and get a clamp on amp meter with multi function options to measure the resistance overall or individualy lol.
[Note} I am an expert at justanswer.com and not familiar with other formats of similar venues. I apologize if my addition to this answer was added out of protocol or if I "stepped on" someones session answer.
[*] (each entity of a circuit has it's own resistive value such as the wire, the heating element, and the devices used to control it which are all added together [Rt=R1 + R2 + R3 + etc....} to make the total resistance.
[**] {current is the amount of electrons that passes through any given point of a circuit for one {1} second known as a coloomb and is measured in "Joules".
The equation for wattage is W = A x V. Substitute your values into this equation and you will have your answer.
The equation you are looking for is Amps = Watts/Volts. To change kW to watts, multiply kW x 1000.
The equation that you are looking for is Amps = Watts/Volts. There are 6000 watts in 6kW.
Watts divided by volts equals amps so 6000 divided by 120 = 50
The calculus operation for finding the rate of change in an equation is differentiation. By taking the derivative of the equation, you can find the rate at which one variable changes with respect to another.
The equation that needs to be used is I = W/E. Amps = Watts/Volts. Amps = 500/240 = 2.08 amps.
There are .42 amps in 420 mA. Equation 420/1000 = .42 amps
The equation that you are looking for is I = W/E. Amps = Watts/Volts.
The equation you are looking for is Watts = Amps x Volts.
You find the equation of a graph by finding an equation with a graph.
There are zero watts in 7.5 amps. Watts are the product of amps times volts. W = A x V. As you can see from the equation a voltage value is missing from your question. Once a voltage value is added to the equation you can find the wattage of the device that draws 7.5 amps.
The equation for wattage is W = A x V. Substitute your values into this equation and you will have your answer.
Amps are related to voltage in the following equation: Watts = Volts * Amps; so in order to answer your question, one would need to know the wattage.
The equation you are looking for is Amps = Watts/Volts. To change kW to watts, multiply kW x 1000.
well the equation for amps is a= watts/volts so 25/12= 2.0833333333amps
The equation that you are looking for is Amps = Watts/Volts. There are 6000 watts in 6kW.
finding the soultion or answer .